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balandron [24]
3 years ago
13

19. Find the perimeter of a triangle if the side lengths are 3 1/2 ft, 5 2/3 ft, and 4 1/6 ft.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer: 13 1/3

Step 1: Find the LCD

Step 2: Add the fractions

Step 3: Simplify

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tamaranim1 [39]
1st answer - he'd pay $751
2nd answer -
7 0
3 years ago
Sally is having a problem with her puppy leaving the yard so she decides to build a new fence. The length of the yard is 7 feet
bezimeni [28]

The length = 6W + 7. 2L + 2W = 70. This is a system of equations. To get L by itself in the second problem, -2W from both sides to get 2L = 70 - 2W. Divide by 2 to get L = 35 - W. Now put them together. 6W +7 = 35 - W. Add W to both sides to get 7W + 7 = 35. Subtract 7 from both sides to get 7W = 28. Divide 7 to both sides to get W = 4. Now replace W with 4. 6(4) + 7 = L. 24 + 7 = 31. The length is 31. To check, do the second equation. 2(31) + 2(4) = 62 + 8 = 70. Your answer is 31.

3 0
3 years ago
I NEED HELP WILL GIVE BRAINLIEST!! PLEASE HELP ME ASAP!!!!
GenaCL600 [577]

Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

∴ hypotenuse = \sqrt{73} = 8.544003745

- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

3 0
3 years ago
Help?
Rashid [163]
*Hint: When a figure is reflective about the y-axis, the rule would be (-x, y)

So as you can see, all the points of the figure changed from a negative x to a positive one but kept the same y value. And then after the translation up by 6 units, the final rule would be (-x, y + 6) and if you were to plug in the points, you would see they would end up as the image.

The answer to this question would be:

B.) Reflection about the y-axis followed by translation up by 6 units.
3 0
3 years ago
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Wesley is making a patio from stones of two sizes, 5 inches wide and 10 inches wide. He wants to begin and end his pattern with
Rom4ik [11]
The first stone will be 10-in wide
The last stone will be 10-in wide
The stones in the middle will be alternating between 5-in and 10-in stones, making a total of 15-in
Total width = 145-in
Width after placing first and last stones = 145 - 20 = 125-in
Number of 15-in patterns incorporated in 125-in:
125/15 = 8.33
Therefore, he will place 8 10-inch stones within and 9 5-inch stones within the patter. 
The total 10-inch stones used = 8 + 2 = 10
3 0
3 years ago
Read 2 more answers
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