All categories

3 years ago

The pressure exerted by a gas on its container is inversely related to its Kelvin temperature

Chemistry

1 answer:

Lelu [443]3 years ago

7 0

False, as pressure increases, temperature increases, given that other factors stay the same.

You might be interested in

How many grams of Sg is required to produce 83.10 g SF6? S: +24F-->8SF

ozzi

Answer : The mass of $S_8$ required is 18.238 grams.

Explanation : Given,

Mass of $SF_6$ = 83.10 g

Molar mass of $SF_6$ = 146 g/mole

Molar mass of $S_8$ = 256.52 g/mole

The balanced chemical reaction is,

$S_8+24F_2\rightarrow 8SF_6$

First we have to determine the moles of $SF_6$ .

$\text{Moles of }SF_6=\frac{\text{Mass of }SF_6}{\text{Molar mass of }SF_6}=\frac{83.10g}{146g/mole}=0.569moles$

Now we have to determine the moles of $S_8$ .

From the balanced chemical reaction we conclude that,

As, 8 moles of $SF_6$ produced from 1 mole of $S_8$

So, 0.569 moles of $SF_6$ produced from $\frac{0.569}{8}=0.0711$ mole of $S_8$

Now we have to determine the mass of $S_8$ .

$\text{Mass of }S_8=\text{Moles of }S_8\times \text{Molar mass of }S_8$

$\text{Mass of }S_8=(0.0711mole)\times (256.52g/mole)=18.238g$

Therefore, the mass of $S_8$ required is 18.238 grams.

7 0

4 years ago

We can also use the equation for enthalpy change for physical phase changes. Consider the phase change H2O(l) → H2O(g). Calculat

BlackZzzverrR [31]

<span>44.0 kJ is the answer</span>

4 0

3 years ago

Read 2 more answers

If I give my teacher chocolate, then she will give me less homework because she will be happier

Softa [21]

Good idea!maybe I should try that

6 0

4 years ago

A boxed 10 kg computer monitor is dragged by friction 5.5 m up along the moving surface of a conveyor belt inclined at an angle

Ede4ka [16]

Answer:

A lot, because it belt inclined at an angle of 36.9° above the horizontal.

I need points haha!

5 0

3 years ago

Read 2 more answers

If the average rate of sediment accumulation is 3 cm/1000years, how long would be required for sediments to completely bury seam

stira [4]

Answer:

500,050000 years

Explanation:

Given that :

Rate of Accumulation = 3cm/ 1000 years

Height of seamounts = 1.5km

Representing height of seamounts in cm;

(1.5 *1000 * 100) = 1500150 cm

Time taken = height / rate

Time taken = (1500150 cm / 3cm) * 1000

Time taken = 500,050000 years

5 0

3 years ago