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rusak2 [61]
3 years ago
14

lX – 12.2l= 0.3 gives the minimum and maximum acceptable lengths of the wires in centimeters. What is the minimum acceptable len

gth of a wire?​
Mathematics
1 answer:
Marianna [84]3 years ago
4 0
<h3>Answer:  11.9 cm</h3>

Work Shown:

|x-12.2| = 0.3

x-12.2 = -0.3 or x-12.2 = 0.3

x = -0.3+12.2 or x = 0.3+12.2

x = 11.9 or x = 12.5

The min length is 11.9 cm and the max length is 12.5 cm

Subtracting 12.2 from either x value leads to a positive difference of 0.3 which is the margin of error.

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Jim writes 10/4words evry day how many words does he write in 10/3 days
ivanzaharov [21]

Answer:

10/4 <em>per</em> day (2.5 words simplified)

10/3 <em>days </em>he wrote so far (around 3 days simplified)

so in order to find out how much he wrote in total multiply the two numbers together

2.5 x 3 = around 7.5 or 8 words

7 0
2 years ago
Tysm3333333333333333333333
geniusboy [140]

Either, The first one or the third one.

6 0
3 years ago
3(x-4)= 2(x + 5) <br> Find the number
ohaa [14]

Answer:

x=22

Step-by-step explanation:

Reorder the terms:

3(-4 + x) = 2(x + 5)

(-4 * 3 + x * 3) = 2(x + 5)

(-12 + 3x) = 2(x + 5)

Reorder the terms:

-12 + 3x = 2(5 + x)

-12 + 3x = (5 * 2 + x * 2)

-12 + 3x = (10 + 2x)

Solving

-12 + 3x = 10 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

-12 + 3x + -2x = 10 + 2x + -2x

Combine like terms: 3x + -2x = 1x

-12 + 1x = 10 + 2x + -2x

Combine like terms: 2x + -2x = 0

-12 + 1x = 10 + 0

-12 + 1x = 10

Add '12' to each side of the equation.

-12 + 12 + 1x = 10 + 12

Combine like terms: -12 + 12 = 0

0 + 1x = 10 + 12

1x = 10 + 12

Combine like terms: 10 + 12 = 22

1x = 22

Divide each side by '1'.

x = 22

Simplifying

x = 22

5 0
3 years ago
1) y = 2 x<br> What’s the vertex,domain,range,x and Y intercept?
Step2247 [10]

Answer:

y and X

Step-by-step explanation:

5 0
4 years ago
If the function h is defined by h(x)=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" a
harkovskaia [24]

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

3 0
3 years ago
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