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jek_recluse [69]
3 years ago
14

Work it -6 - 2m = 10

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
6 0
Add 6 to both sides>>><span>−-2m=10+6
</span>Simplify <span>10+6 </span><span>to </span>16>>><span>−-2m=16
</span><span>Divide both sides by -</span>−2>>><span>m=<span>16/<span>−-2
</span></span></span>Simplify <span>16/<span>−2</span></span><span> to -</span><span>−16/2>>>></span>m=-<span>16/−2
</span>Simplify <span>16/2</span> to 8>>>>m=-−8

Answer m=-8
Nadusha1986 [10]3 years ago
3 0

Hi there!


To solve for your equation, first, it would be a little helpful to rewrite it, as it looks easier to work out.


-6 - 2m = 10


Let us begin!


Step 1) Simplify both sides of the equation. (Below are the steps on how to simplify!)


-6 + -2m = 10 -2m - 6 = 10


Pretty simple to simplify! :D


Step 2) Add 6 to both sides.


-2m - 6 + 6 = 10 + 6 - 2m = 16


Pretty easy so far!


Step 3) Divide both sides by -2.


\frac{-2m}{-2} =  \frac{16}{-2}  m = -8


Final Answer -


m = -8


See, it wasn't so bad! If anything, it was too easy! :)


Hope this helps! :D

Message me if you need anymore help with anything!

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A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
3 years ago
If (14,25) and (9,-10) are two anchor points on a trend line, then find the equation of the line.
posledela

Answer:

y= 7x-73

Step-by-step explanation:

the equation form is y=mx+c where m is the slope and c a constant

m= (25-(-10))/14-9 = 35/5 = 7

so y= 7x+c

replace x and y by 14 and 25 respectively

25 = 7*14+c

c= 25-7*14

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