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Firdavs [7]
3 years ago
13

A program is expressed in a programming language. Whiat is true of the program?

Computers and Technology
1 answer:
zalisa [80]3 years ago
4 0

Answer:

The answer is "The program can also be expressed as a binary code, but it is easier for people to understand when it is expressed in a higher programming language".

Explanation:

In the given question some details are missing that is options of the question that can be given as follows:

A. The program can also be expressed as a binary code, but it is easier for people to understand when it is expressed in a higher programming language.  

B. The program can also be represented as a binary code that reduces the likelihood of errors.  

C. Binary code can not be used for binary code, because binary code can only represent data.  

D. Some parts of the program, however, should be printed in a higher-level language for the operation.  

The computer knows the only binary language, It is a form of 0 and 1, but this language can't be understood by the user. It will convert into high-level language, that is understood by the user, that's why this option is correct.  In which accepts of option A, all options are wrong that can be described as follows:

  • In option B, It is wrong, because the user may not understand binary language, and he can also be writing some wrong code that is converted in binary code, that will increase error.
  • In option C and option D, is incorrect because all the data that is stored in the computer is in the form of binary code.

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Which of the following are some popular debugging techniques?
topjm [15]

Answer:

a fix any syntax bugs. I looked it up on the internet so you should be good good luck on your test

8 0
3 years ago
If x has a value of 7 and y has a value of 20, what is displayed as a result of executing the code segment
Llana [10]

<em>6.65 </em><em>is displayed as the</em><em> output </em><em>of the </em><em>block of code</em>

<em />

In python programming, * denotes multiplication. To get the output, we will substitute the value of x and y given into the result to have;

<em> result = x * y - x / (y)</em>

<em> result = 7 * 20 - 7 / (20)</em>

<em> result = 140 - 7 / (20)</em>

<em> result = 133/20</em>

<em> result = 6.65</em>

<em />

<em>This shows that </em><em>6.65 </em><em>is displayed as the</em><em> output </em><em>of the </em><em>block of code</em>

<em />

The question is incomplete;

Let the code segment be

<em>>>> x = 7 </em>

<em>>>> y = 20   </em>

<em>>>> result = x * y - x / (y) </em>

<em>>>> result  </em>

<em>output:__?</em>

<em />

Learn more here: brainly.com/question/24240957

5 0
3 years ago
Many types of academic writing require multiple sources ?<br><br> True<br><br> False
ValentinkaMS [17]

Answer:

True!

Explanation:

A few types that need them are;

News articles

Narratives

Opinion writes

Etc

6 0
3 years ago
Read 2 more answers
The mean of a sequence of n numbers is m. If we split the sequence into two sequences of lengths n1 and n2 and compute their mea
ANTONII [103]

The mean of a sequence of numbers is the average.

The true statement is: \mathbf{mn = m_1n_1 + m_2n_2}

The given parameters are:

\mathbf{Mean=m}

\mathbf{Size=n}

The mean of a dataset is calculated as:

\mathbf{Mean = \frac{Sum}{Count}}

So, we have:

\mathbf{m = \frac{Sum}{n}}

Multiply both sides by m

\mathbf{Sum = mn}

When the sequence is split into two, we have:

\mathbf{\sum x_1 = m_1n_1}

\mathbf{\sum x_2 = m_2n_2}

Where:

\mathbf{Sum = \sum x_1 + \sum x_2}

So, we have:

\mathbf{mn = m_1n_1 + m_2n_2}

Hence, the true statement is: \mathbf{mn = m_1n_1 + m_2n_2}

Read more about mean and averages at:

brainly.com/question/25421763

5 0
3 years ago
Write a C++ program which prompts user to choose from the two alternative funtions specified below, each of which passes a rando
melomori [17]

Answer:

#include <iostream>   //header file

#include <stdlib.h>    

#include <time.h>      

using namespace std;       // using namespace

string call_by_value(int num)    // call by value

{

  if(num==1)

  return "hello sir!";

  if(num==2)

  return "what's going on?";

  if(num==3)

  return "howz you master?!";

  if(num==4)

  return "i m fine!";

}

string call_by_reference(int *num)       //call by reference

{

  if(*num==1)

  return "hello sir!!";

  if(*num==2)

  return "what's going on?";

  if(*num==3)

  return "howz you master?";

  if(*num==4)

  return "i m fine";

}

int main() {                      //main function

  int n,v,r;

  string str;

  srand (time(NULL));

  cout<<"enter a value 1 and 2 for choice and -1 for exit : ";

  cin>>n;

  while(n!=-1)

  {

      if(n==1)

      {

          int num = (rand()%(4)) + 1;

          str=call_by_value(num);

          cout<<str<<endl;

      }

      else if(n==2)

      {

          int num = (rand()%(4)) + 1;

          str=call_by_reference(&num);

          cout<<str<<endl;

      }

      else

      cout<<"invalid input !"<<endl;

      cout<<"enter a value 1 and 2 for choice and -1 for exit :";

      cin>>n;

  }

  return 0;

}

Explanation:

Firstly, we declare three header files, then use namespace

Then, create the module of call by value and then call by reference.

Then we define the main() function in which we call both the modules.

3 0
3 years ago
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