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3 years ago

5/6 divided by 1/4 as a fraction Please ASAP!! <3

Mathematics

2 answers:

ivann1987 [24]3 years ago

8 0

Answer:

10/3

Step-by-step explanation:

(5/6) / (1/4) = (5/6) x (4/1) = (5/3) x (2/1) = 10/3

lianna [129]3 years ago

8 0

if needed only as a fraction:

20/6

3.34/1

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4 years ago

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4 years ago

Explain how to add fractions with unlike denominators. Please be as specific as possible.

Gelneren [198K]

Answer:

Look below

Step-by-step explanation:

So I will use an example to try and show you how to do this.

If we have $1/2 + 1/3$ , we know that we don't have like denominators. We can change this by finding one. All we need to do is multiply our denominators. So in our example, that would be $2*3=6$ . Our new denominator would be 6. So now we would have $1/6 + 1/6$ which isn't the same as our old equation. That is because we haven't multiplied our top numbers yet. To do this, we need to multiply the top number by the opposite denominator like so, $3/6+2/6$ .

So our first fraction was

$1/2+1/3$

We then multiplied the whole fraction by the opposite denominator

$3/6+2/6$

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3 years ago

What are the steps for constructing a copy of an angule only a compass and a straightedge

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With one point of the compass on the vertex of the angle, draw an arc that intersects both sides of the angle. Draw an arc from each of these points of intersection so that the arcs intersect<span> in the interior of the angle. The compass needs to </span>stay open<span> the same amount throughout this step.

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4 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

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3 years ago