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3 years ago

How to prove two equations have infinite solutions?

1 answer:

6 0

To prove two equations have infinite solutions, you have to prove that those two equations are the same equations, but in a different form.

For example: Prove the equations are infinite
5y=2x+7
10y=4x+14
If you multiply the first equation by 2, and substitiute any of the numbers, you will get 0=0

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3 years ago

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Which of these 3-dimensional shapes is composed of only square faces?

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Answer:

d.Cube

Step-by-step explanation:

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If f(x) = 1 – x2 + x3, then f(-1) =

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Answer:

Step-by-step explanation:

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3 years ago

Which graph shows the solution to the system of linear inequalities?

Vadim26 [7]

Answer:

Observe the attached image.

Step-by-step explanation:

We have the following linear inequalities

$y > \frac{2}{3}x + 3\\\\y \leq \frac{1}{3}x + 2$

Graph the lines corresponding to each inequality

$y > \frac{2}{3}x + 3$ → $y = \frac{2}{3}x + 3$

Cut with the y axis:

y = 3

Cut with the x axis:

$0 = \frac{2}{3}x + 3$

$-3 = \frac{2}{3}x$

$x = -4.5$

$y \leq \frac{1}{3}x + 2$ → $y = \frac{1}{3}x +2$

Cut with the y axis:

y = 2

Cut with the x axis:

$0 = \frac{1}{3}x + 2$

$-2 = \frac{1}{3}x$

$x = -6$

Now graph the two lines

For $y > \frac{2}{3}x + 3$

The region is made up of all the points that are above the line $y =\frac{2}{3}x + 3$

For $y \leq \frac{1}{3}x + 2$

The region is made up of all the points that are on the line and below $y = \frac{1}{3}x +2$

The final region will be the interception of both regions

Observe the attached image.

The system shown in the image you attached is:

$y > \frac{2}{3}x + 3\\\\y \leq -\frac{1}{3}x + 2$

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4 years ago

What is the distance between point A and point B to the nearest tenth?

drek231 [11]

The answer is C. If you use the pythagorean theorem, $a^2+b^2=c^2$ , and connect the two points together at a right angle and pug in the lengths of the two lines to the equation then the answer should be C.

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4 years ago