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djverab [1.8K]
3 years ago
11

How to prove two equations have infinite solutions?

Mathematics
1 answer:
laiz [17]3 years ago
6 0
To prove two equations have infinite solutions, you have to prove that those two equations are the same equations, but in a different form.

For example: Prove the equations are infinite
5y=2x+7
10y=4x+14
If you multiply the first equation by 2, and substitiute any of the numbers, you will get 0=0
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A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?
Tasya [4]
It should be 7.97 decigrams, since you want to convert 3 milligrams to decigrams (0.03), it is asking "How much more" which means you subtract.  8 subtracted from 0.03 is 7.97.

Hope this helps :)

8 0
3 years ago
Read 2 more answers
James has eight coins in his pocket. All the coins are either dimes or quarters.The total value of the coins is $1.25. How many
Goshia [24]

Answer:

he has 5d+3q

Step-by-step explanation:

since every d is .10 and every q is .25 the equation can be changed to 5(.10)+3(.25) which is equal to .5+.75 which adds up to 1.25

i did this by assuming that the amount of d is 8 at first, then change one of the 8 d to a q which will give you 7d+q, then assume another d is a q which will give you 6d+2q, repeat this until the amount of d and q add up to 1.25

6 0
3 years ago
A polygon has the following coordinates: A(2,-3), B(-2,3), C(2,2). What is the length of AC?
kkurt [141]

Answer:

5 units

Step-by-step explanation:

7 0
3 years ago
A 30 feet ladder is leaning against the wall. The top of the ladder is resting 25 feet on the building. How far is the base of t
g100num [7]

Answer:

16.58 feet

Step-by-step explanation:

a² + b² = c²

Think of this as a right triangle

The hypotenuse is 30, and one of the legs is 25

To find the other leg, subtract the square of the hypotenuse by the square of the given leg

30² - 25² = leg

900 - 625 = 275

Square root the answer to find the length of the missing leg

√275 = 16.583123951777

The leg is 16.58 ft.

6 0
2 years ago
Write an equation of the line that is perpendicular to 3x - 4y equals 9 + contains (-4, -5)
Inga [223]
  • Slope-Intercept Form: y = mx+b, with m = slope and b = y-intercept

So perpendicular lines have <u>slopes that are negative reciprocals</u> to each other, but firstly we need to find the slope of the original equation. The easiest method to find it is to convert this standard form into slope-intercept.

Firstly, subtract 3x on both sides of the equation: -4y=-3x+9

Next, divide both sides by -4 and your slope-intercept form of the original equation is y=\frac{3}{4}x-\frac{9}{4}

Now looking at this equation, we see that the slope is 3/4. Now since our new line is perpendicular, this means that <em>its slope is -4/3.</em>

Now that we have the slope, plug that into the m variable and plug in (-4,-5) into the x and y coordinates to solve for the b variable as such:

-5=-\frac{4}{3}*-4+b\\\\-5=5\frac{1}{3}+b\\\\-10\frac{1}{3}=b

<u>In short, your new equation is y = -4/3x - 10 1/3.</u>

3 0
3 years ago
Read 2 more answers
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