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3 years ago

6

Monica ran 20 miles in two days. How many miles did she run each day, if she ran 4 more miles on the second day than on the firs

t day?
On the first day she ran _____________ miles, and on the second day she ran _______ miles.

2 answers:

AlekseyPX3 years ago

4 0

Answer:

$in \: day \: one \: she \: ran \: 8 \: mile s.\\ in \: day \: two \: she \: ran \: 12 \: miles.$

Step-by-step explanation:

$let \: the \: number \: of \: miles \: for \: the \: first \: day \: be : x \\ let \: the \: number \: of \: miles \: for \: the \: second \: day \: be : x + 4 \\ therefore \: in \: two \: days \: she \: ran \: 20 \: miles = x + (x + 4) \\ now......thats \: the \: required \: equation....... \\ if \: x + (x + 4) = 20 \: then : \\ 2x + 4 = 20 \\ 2x = 20 - 4 \\ 2x = 16 \\ x = 8. \\ so \: in \: day \: one \: she \: ran \: 8 \: mile \\ in \: day \: two \: she \: ran \: (8 \: + 4) \: miles = 12 \: miles$

its so funny how you reacted to the other helper

♨Rage♨

Serhud [2]3 years ago

3 0

Answer:

6 miles on the first day and 14 miles on the second day

Step-by-step explanation:

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2 years ago

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Remark

The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.

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<u>Upper Limit</u>

$\dfrac{11}{16} + \dfrac{1}{64}$

Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4

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Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.

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Step-by-step explanation:

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