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KatRina [158]
3 years ago
11

You purchased 100 shares of stock valued at $55 per share. The stock value increases to $85 per share. What was the rate of incr

ease?
Mathematics
1 answer:
guapka [62]3 years ago
6 0
Answer: $30 per share.

Explanation:
55 + x = 85
-55 -55
x 30
x = 30
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100+16=116 is the right answer
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47 is 10 less than my number.<br> 67 is 10 more than my number.<br> What is my number
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Your number is 57.
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3 years ago
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find the circumference of each circle with the given radius or diameter round to the nearest tenth use 3.14 for pie r=9 cm
Sphinxa [80]

Answer:

d=2r

Step-by-step explanation:

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3 years ago
The number of rookie cards in a variety pack of baseball cards is normally distributed with a mean of 3 cards and the standard d
Sergio039 [100]

Answer:

z = \frac{2-3}{\frac{1}{\sqrt{10}}}=-3.163

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P(-3.163

P(-3.163

So then we will expect 9.98 packages between 2-4 rookie cards in the sample of 10

Step-by-step explanation:

Let X the random variable that represent the number of rookie cards of a population, and for this case we know the distribution for X is given by:

X \sim N(3,1)  

Where \mu=3 and \sigma=1

We select a sample size of n = 10 variety packs and we want to find this probability:

P(2

We can use the z score formula given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

We can find the z score for 2 and 4 and we got:

z = \frac{2-3}{\frac{1}{\sqrt{10}}}=-3.163

z = \frac{4-3}{\frac{1}{\sqrt{10}}}=3.163

So we can find the probability with this difference

P(-3.163

And using the normal standard distirbution or excel we got:

P(-3.163

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4 0
3 years ago
Find formula of s in terms of a, b, cos(x)
Alecsey [184]

Answer:

\displaystyle s = \frac{2ab\cos x}{a+b}

Step-by-step explanation:

We want to find a formula for <em>s</em> in terms of <em>a, b, </em>and cos(x).

Let the point where <em>s</em> intersects AB be D.

Notice that <em>s</em> bisects ∠C. Then by the Angle Bisector Theorem:

\displaystyle \frac{a}{BD} = \frac{b}{AD}

We can find BD using the Law of Cosines:

\displaystyle BD^2 = a^2 + s^2 - 2as \cos x

Likewise:

\displaystyle AD^2 = b^2+ s^2 - 2bs \cos x

From the first equation, cross-multiply:

bBD = a AD

And square both sides:

b^2 BD^2  =a^2 AD^2

Substitute:

\displaystyle b^2 \left(a^2 + s^2 - 2as \cos x\right) = a^2 \left(b^2 + s^2 - 2bs \cos x\right)

Distribute:

a^2b^2 + b^2s^2 - 2ab^2 s\cos x = a^2b^2 + a^2s^2 - 2a^2 bs\cos x

Simplify:

b^2 s^2 - 2ab^2 s \cos x = a^2 s^2 - 2a^2 b s \cos x

Divide both sides by <em>s </em>(<em>s</em> ≠ 0):

b^2 s -2ab^2 \cos x = a^2 s - 2a^2 b \cos x

Isolate <em>s: </em>

b^2 s - a^2s = -2a^2 b \cos x + 2ab^2 \cos x

Factor:

\displaystyle s (b^2 - a^2) = 2ab^2 \cos x - 2a^2 b \cos x

Therefore:

\displaystyle s = \frac{2ab^2 \cos x - 2a^2 b \cos x}{b^2- a^2}

Factor:

\displaystyle s = \frac{2ab\cos x(b - a)}{(b-a)(b+a)}

Simplify. Therefore:

\displaystyle s = \frac{2ab\cos x}{a+b}

5 0
3 years ago
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