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Tatiana [17]
3 years ago
7

Multiple Choice. Which of the following fractions is equivalent to 6/15

Mathematics
2 answers:
Lemur [1.5K]3 years ago
5 0

Answer:

2/5

Step-by-step explanation:

Fittoniya [83]3 years ago
5 0

Answer:

the answer that is equivalent to 6/15 is 4/10

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How do I draw perpendicular line
taurus [48]

Answer:

Follow these steps and you will find how to make a perpendicular line.

Step-by-step explanation:

Open the compass to a radius less than half the segment.

Draw two arcs intersecting the line on both sides of the point.

Draw two arcs using the intersection points as the centers. ...

Construct a line between this point and the original point.

Hope this helped :) -ish

5 0
2 years ago
Beth has 250 comic books in her collection. She begins to sell 20 of them each week. Martin has 80 comic books in his collection
Nuetrik [128]
Well, after doing all that math, here is what I came up with, I hope this helps! :) -1600x^2+28265x-21830
6 0
3 years ago
Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14
kodGreya [7K]

Answer:

x = 3  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3  , y = -2

5 0
3 years ago
Read 2 more answers
Please answer this 18-34+49×200÷2​
Kazeer [188]
4884

.................
7 0
3 years ago
A rancher needs to enclose two adjacent rectangular​ corrals, one for cattle and one for sheep. If the river forms one side of t
Serga [27]
Basically, what this asks you is to maximize the are A=ab where a and b are the sides of the recatangular area (b is the long side opposite to the river, a is the short side that also is the common fence of both corrals). Your maximization is constrained by the length of the fence, so you have to maximize subject to 3a+b=450 (drawing a sketch helps - again, b is the longer side opposite to the river, a are the three smaller parts restricting the corrals)
3a+b = 450
b = 450 - 3a
so the maximization max(ab) becomes
max(a(450-3a)=max(450a-3a^2)
Since this is in one variable, we can just take the derivative and set it equal to zero:
450-6a=0
6a=450
a=75
Plugging back into b=450-3a yields
b=450-3*75
b=450-225
b=215
Hope that helps!
5 0
3 years ago
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