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3 years ago

Can someone help please!

Mathematics

1 answer:

faust18 [17]3 years ago

8 0

Answer:a) 0.35

B) 0.75

C) 0.65

D) 0.25

E) 1.1

F) 0.9

Step-by-step explanation:

Relative frequency= frequency/total number of value

A) 21/60= 0.35

B) 135/180= 0.75

C) 39/60= 0.65

D) 45/180= 0.25

E) Rf Male or female choosing sport utility car = 21/60 + 135/180 = 0.35 + 0.75= 1.1

F) Rf of male or female choosing a sport car= 39/60 +45/180= 0.65 + 0.25= 0.9

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Then

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By DeMoivre's theorem,

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2 years ago

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3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

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Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

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2 years ago

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julia-pushkina [17]

Answer:

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Step-by-step explanation:

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Answer:

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2 years ago