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Evgesh-ka [11]
3 years ago
7

A landscaping company sells bushes for $24 each and trees for $36 each. If you spent $648 on materials, complete the statements

below. a. Complete the tables showing three ways you could have spent $648 on bushes and trees. Show your work. ​

Mathematics
1 answer:
Fynjy0 [20]3 years ago
4 0
#of bushes, x #of trees, y

18 6
12 10
6 14
Explanation:
Do you mind if you make the explanation? Try to find out for urself atleast u do something. Its kinda easy tbh.
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PLEASE ANWSER THIS!!!!
Rainbow [258]

Answer:

14 in^2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction b
deff fn [24]

Answer:

B

Step-by-step explanation:

Assuming the denominator is 16 (to fit with the second part), 9+3 is 12 and 12/16 is 3/4.

If we take 7 from 16 we also get 9, which is thus 1.

4 0
4 years ago
What is the Lcm for 5,6,7
Debora [2.8K]

The three numbers have no prime divisors in common:

5=5,\quad 6=2\times 3,\quad 7=7

So, the least common multiple is the product of the numbers:

\text{LCM}(5,6,7)=5\times 6\times 7 = 210

7 0
4 years ago
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Erin feeds her dog 7/10 cup of food a day . With 3/10 cup canned and the rest dry . She also gives her dog 1 treat a day . How m
gavmur [86]

Answer:

2\frac{4}{5}\ \ or \ 2.8 \ \ cups

Step-by-step explanation:

-The total portion fed to the dog is 7/10 cup

  • Canned-3/10
  • Dry=7/10-3/10=4/10

-One week has 7 days. we multiply the dry portion per day by the number of days in a week.

Dry= Total -Canned\\\\=\frac{7}{10}-\frac{3}{10}\\\\=0.40 \ cup\\\\Dry \ per \ Week= Dry/ day\times days\\\\=0.40\times 7\\\\=2\frac{4}{5}\  or\  2.8 \ cups

Hence, Erin feed her dog 2 4/5 0r 2.8 cups of dry food

5 0
3 years ago
A survey found that the American family generates an average of 17.2 pounds of glass garbage trash each year. Assume the standar
SIZIF [17.4K]

Answer: 0.8137

Step-by-step explanation:

As per given , we have

\mu= 17.2\ ,\ \sigma=2.5

Sample size : n= 47

Let \overline{X} be the sample mean o.

Then, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds will be :

P(16.6

=P(-1.645

[∵ z= \dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]

=P(z

=0.8636793-(1- 0.9500151)  [By using p-value calculator]

=0.8636793-0.0499849=0.8136944\approx0.8137

Hence, the probability that the mean of a sample of 47 families will be between 16.6 and 17.6 pounds= 0.8137

6 0
4 years ago
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