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blagie [28]
3 years ago
5

Can someone please help me? ASAP

Mathematics
1 answer:
Dmitry [639]3 years ago
8 0

Answer:

A

Step-by-step explanation:

3^5 x 3^4

=3^5 + 4

=3^9

so the answer is option A

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Can anyone one help me with this question
n200080 [17]
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5 0
3 years ago
880,005 rounded to the nearest hundred thousand what is the answer
ycow [4]

Answer:

900,000

Step-by-step explanation:

I'm not sure how to explain rounding, but this should be the answer if ur asking for rounding to the nearest hundred thousand and not the hundredth thousand

5 0
3 years ago
Read 2 more answers
A runner is 6/8 mile from the finish line. If she can travel 3/8 mile per minute, how long will it take her to finish the race?
Klio2033 [76]

Answer:

it will take her 40 seconds to finish the race.

3/8 per minute, would make it 1/8 every 20 seconds. since she only has 2/8 of a mile left to go, 20 seconds +20 seconds = 40 seconds

(if you needed how long it takes her to run the whole race, it's 2 minutes 40 seconds, which would make her the fastest mile runner in the world)

Step-by-step explanation:

I hope this helps :)

6 0
3 years ago
The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim
Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

34.5 + 20.75 + 24.75 = 80cm.

Hope this helped.

3 0
2 years ago
Particle 1 of charge q1 �� ��5.00q and particle 2 of charge q2 �� ��2.00q are fixed to an x axis. (a) as a multiple of distance
Naya [18.7K]

<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>

Rearranging to calculate for d:

<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0  
d = 2.72075922005613 
d = 0.612574113277207 </span>

<span>
We pick the value that is > q2 hence,</span>

d = 2.72075922005613*L

<span>d = 2.72*L</span>

3 0
3 years ago
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