Hydrogen + oxygen -> water
2H2 + O2 -> 2H2O (balanced)
2 moles of hydrogen gas will react with 1 mole of oxygen to produce 2 moles of water.
following that ratio, 0.734 mole of oxygen must need 0.734 × 2 moles of hydrogen to fully react.
answer is 1.468 moles of hydrogen.
The reaction will be spontaneous if Gibb free energy is negative, according the following relation:
G = H - T*S
where G is Gibbs free energy, T is change of enthalpy , T is temperature and S is change of entropy
In the case of ammonia:
G = -93000 - 356*(-198) = -93000 + 70488 = -22512 j/mol
As G < 0 then the reaction is spontaneous.
Answer:
Partial pressure of methane: 1.18 atm
Partial pressure of ethane: 1.45 atm
Partial pressure of propane: 2.35 atm
Explanation:
Let the total moles of gases in a container be n.
Total pressure of the gases in a container =P = 5.0 atm
Temperature of the gases in a container =T = 23°C = 296.15 K
Volume of the container = V = 10.0 L
(Ideal gas equation)

Moles of methane gas =
Moles of ethane gas =
Moles of propane gas =


Partial pressure of all the gases can be calculated by using Raoult's law:

= partial pressure of 'i' component.
= mole fraction of 'i' component in mixture
P = total pressure of the mixture
Partial pressure of methane:


Partial pressure of ethane:


Partial pressure of propane:


Answer:
The following three isomeric structure are given below.
Explanation:
Structure of the following three isomeric esters with chemical formula C₇H₁₂O₂
Ester #1: methyl 1-methylcyclobutanecarboxylate
Ester #2: (E)-methyl 3-methyl-3-pentenoate
Ester #3: isopropyl 2-methylpropenoate
Formation of hydrates is considered to be a chemical change.