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trasher [3.6K]
3 years ago
15

1)Water takes this form above 100c (solid, liquid or gas)

Chemistry
1 answer:
olga55 [171]3 years ago
5 0

Answer:

I say the 1st one I'm so terrible sorry if I'm wrong

Explanation:

Water can take many forms. At low temperatures (below 0°C), it is a solid. When at “normal” temperatures (between 0°C and 100°C), it is a liquid. While at temperatures above 100°C, water is a gas (steam).

The state the water is in depends upon the temperature.  Each state (solid, liquid, and gas) has its own unique set of physical properties.

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Neon is an inert gas and has the atomic number of 10. Which of the following correctly depicts its electron configuration? 1s22d
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10 Ne:

1s², 2s², 2p⁶

Answer C

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A reaction which needs to gives off energy to complete the chemical reactions is called an
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Exothermic reaction

Explanation:

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Which number is equal to -906,060?
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4 years ago
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andrey2020 [161]

3. Cl₂ + 2KI --> 2KCl + I₂

Cl = 2        Cl = 2

K = 2         K = 2

I = 2           I = 2

4. 2NaCl --> 2Na + Cl₂

Na = 2      Na = 2

Cl = 2       Cl = 2

5. 4Na + O₂ --> 2Na₂O

Na = 4      Na = 4

O = 2        O = 2

6. 2Na + 2HCl --> H₂ + 2NaCl

Na = 2         Na = 2

H = 2           H = 2

Cl = 2          Cl = 2

7. 2K + Cl₂ --> 2KCl

K = 2         K = 2

Cl = 2        Cl = 2

8 0
3 years ago
6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperatu
Otrada [13]

Answer:

a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

  • Volume of the chamber (V): 200. L
  • Room temperature (T): 23 °C
  • Pressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

m = 24.7 mol × 32.00 g/mol = 790 g

6 0
3 years ago
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