The balanced equation for the above reaction is as follows; 2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O stoichiometry of octane to CO₂ is 2:16 number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol when 2 mol of octane reacts it forms 16 mol of CO₂ therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂ number of CO₂ moles formed - 13.45 mol therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g mass of CO₂ formed is 591.8 g