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Wewaii [24]
3 years ago
15

If √3 = 1.73 to 2 dp, find the value of 4/√3 to 2 dp​

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:2.31

Step-by-step explanation: considering that the root of 3 has already been given. Will just divide 4 by the root of 3 which is 1.73. and the answer it gives is 2.31

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Step-by-step explanation:

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3 years ago
A rectangular filed is 190m by 270m . A rectangular barn is 23 m by 40 m is built in the field .
Anika [276]

Answer: 50,380m

Step-by-step explanation:

190m * 270m = 51,300m

23m * 40m = 920m

Because the barn is in the field, we subtract the barn's area from the field's area, which leaves us with

51,300m - 920m = 50,380m

4 0
3 years ago
Help me out the number inside the triangle is really throwing me off tbh
prisoha [69]

We are given an angle of 60° and a side of 15 cm.

We are given the opposite and is looking for the hypotenuse so we will use the sine ratio to find x.

sin = opp/hyp

hyp = 15 / sin 60

hyp = 17.32...

//

We can also use the tangent ratio to find the adjecent and then use pythagorean to find x.

tan = opp/adj

adj = 15 / tan 60

adj = 8.660.....

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6 0
3 years ago
The table shown below gives the approximate number of pieces of mail handled by the United States Postal Service for different y
netineya [11]

Answer:

Step-by-step explanation:

Answer:

1.08×10^11

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4 0
3 years ago
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
-Dominant- [34]

Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

5 0
3 years ago
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