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larisa [96]
3 years ago
15

The legs of an isosceles right triangle are 5 inches long. What is the length of the hypotenuse of the triangle to the nearest i

nch?
Mathematics
2 answers:
In-s [12.5K]3 years ago
6 0
The legs are 5 inches long.

Use the Pythagorean theorem:
5^2+5^2=c^2 \\
25+25=c^2 \\
50=c^2 \\
c=\sqrt{50} \\
c=\sqrt{25 \times 2} \\
c=5 \sqrt{2} \\
c \approx 7

The length of the hypotenuse of the triangle is approximately 7 inches long.
luda_lava [24]3 years ago
5 0
a^{2} + b^{2} = c^{2}  \\  5^{2} + 5^{2} = c^{2}  \\  25 + 25 = c^{2}  \\ 50= c^{2}  \\  \sqrt{50}= c \\ c=7.07
c ≈ 7

The hypotenuse is about 7 inches long.

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The answer to this is (2,0)
7 0
3 years ago
What is the value of x in the solution
krok68 [10]

Answer:

x =\dfrac 47

Step-by-step explanation:

~~~~~9x-1 = 2x+3\\\\\implies 9x -2x = 3+1\\\\\implies 7x = 4\\\\\implies x =\dfrac 47

6 0
2 years ago
Pls help I dont know how to do this​
german

Answer:

  • 1. CE = 63
  • 2. x = 16

Step-by-step explanation:

Use proportions to solve.

Corresponding sides have same ratio.

<u>Question 1</u>

  • DE/EG = CE/EF
  • (6x + 3)/17 = (8x - 1)/21
  • 21(6x + 3) = 17(8x - 1)
  • 126x + 63 = 136x - 17
  • 10x = 80
  • x = 8
  • CE = 8*8 - 1
  • CE = 63

<u>Question 2</u>

  • KM/MD = KZ/ZH
  • (x + 8)/21 = 32/28
  • x + 8 = 21*8/7
  • x + 8 = 24
  • x = 24 - 8
  • x = 16
5 0
3 years ago
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
horsena [70]

Answer:

x^{4} -18x^{3}+104x^{2} -172x-100

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:  

\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

7 0
2 years ago
Gordon was thinking of a number. Gordon doubles it and gets an answer of 90.8. What was the original number?
zalisa [80]

Answer:

45.4

Step-by-step explanation:

Nx2=90.8

Divide both sides by 2

N=45.4

8 0
3 years ago
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