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Sonbull [250]
3 years ago
15

HELP ME WITH THIS QUESTION ASAP

Mathematics
1 answer:
Stels [109]3 years ago
8 0
Factor out 12x^3y^2

12x^3y^2(3y^2+5x^ 2 y z^2 -1)
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4^x-4^x-1=24,then find (2x)^x
DENIUS [597]

Answer:  5²⁻⁵

<u>Step-by-step explanation:</u>

4^x-4^{x-1}=24\\\\\\3(4^{x-1})=24\\\\\\4^{x-1}=8\\\\\\2^{2(x-1)}=2^3\\\\\\2(x-1)=3\\\\\\x-1=\dfrac{3}{2}\\\\\\x=\dfrac{5}{2}\quad \rightarrow x=2.5

(2x)^x\quad =(2\cdot 2.5)^{2.5}\quad =\large\boxed{5^{2.5}}

7 0
3 years ago
Please help with these 2 answers i only have 10 minutes left
natta225 [31]

Answer:

  1. 1/4 of a pound
  2. 4/15 of the flat

Step-by-step explanation:

For number 1:

  1. 3/4 ÷ 3 = 0.25
  2. 0.25 = 1/4

For number 2:

  1. 4/5 ÷ 3 = 4/15

I hope this helps!

5 0
3 years ago
Read 2 more answers
y = 3x + 3 y = x − 1 Explain how you will solve the pair of equations by substitution. Show all the steps and write the solution
Leona [35]
Y = 3x + 3
y = x - 1

As you can see, both equations are set to equal y. This means the right sides of each equation are equal, since y is isolated in both equations. So to solve this particular system of equations for x, set the right sides of both equations equal to each other. After you've done that, you can proceed to solve the equation algebraically for the variable, x.

3x + 3 = x - 1
2x + 3 = -1
2x = -4
x = -2

Negative two is the x-value. To find the y-value, substitute -2 for x into either equation and solve algebraically for y.

y = x - 1
y = -2 - 1
y = -3

The final step is to check all work by plugging both x- and y-values back into both equations.

y = 3x + 3
-3 = 3(-2) + 3
-3 = -6 + 3
-3 = -3  --  This is true

y = x - 1
-3 = -2 - 1
-3 = -3  --  This is true.

Answer:
(-2, -3)
5 0
4 years ago
PLZ HELP ME I NEED IT
Marianna [84]

Answer:

im looking at B! hope this helps!


Step-by-step explanation:


8 0
3 years ago
Select the correct answer.
dolphi86 [110]

Answer:

your answer gonna be the letter D 20

6 0
3 years ago
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