Answer:
Nice to hear that, congrats with practice 7.3
Answer:
3.333333333333...
Step-by-step explanation:
when a data consists of hundreds of values
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>pls</u><u> </u><u>mark</u><u> </u><u>me</u><u> </u><u>as</u><u> </u><u>brainliest</u>
As we know that cotx= 1/tanx
cot36° = 1/tan36°
=>cot36°= 1/0.726543
=>so cot 36°= 1.376382
So correct answer is option D.
HOPR YOU LIKED.
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
