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irakobra [83]
3 years ago
13

I need help I don’t get it and it’s hard can someone help me

Mathematics
2 answers:
Pavel [41]3 years ago
6 0

Answer:

The answer is (4)  2x+x^{2} +4x^{3}.

Step-by-step explanation:

A leading coefficient is the coefficient of the term of highest degree in a given polynomial.  

A degree of a polynomial is the largest exponent on one of its variables (for a single variable), or the largest sum of exponents on variables in a single term (for multiple variables).

The answer can be found when the polynomial is rearranged into standard form, and the standard form of the polynomial will look like 4x^{3}+x^{2} +2x. A polynomial is in standard form when the term with the highest degree is placed first, followed by the term which has the next highest degree, and so on.

Once the polynomial is in standard form, the leading coefficient is 4 and has a degree of 3. Thus, causing (4) 2x+x^{2} +4x^{3} to be the answer.

DedPeter [7]3 years ago
3 0

Answer:

choice 4

Step-by-step explanation:

It's not that hard if you understand once you get past the fancy words

degree= largest exponent

so if something has a degree of 3 we know that the highest exponent is 3

Coeficcent= thing multipllying x

in this case it's 4 which means the number we are looking for is 4x³

Onlyanswer choice 4 meets these criteria

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4 years ago
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sergejj [24]

Answer:

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Step-by-step explanation:

Hello!

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Hope this helps!

7 0
3 years ago
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Solutions to -8x + 5 less than or equal to 11
Vilka [71]

Answer:

x\geq -\frac{3}{4}

Step-by-step explanation:

-8x+5\leq 11\\\\1. -8x\leq 11-5\\   -8x\leq 6

Isolate the parts of the equation with the x variable

2. \frac{-8}{-8} x\geq\frac{6}{-8}  \\x\geq -\frac{3}{4}

When you divide or multiply by a negative number in inequalities, you must flip the sign of the inequality.

5 0
3 years ago
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Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
horsena [70]

Answer:

x^{4} -18x^{3}+104x^{2} -172x-100

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:  

\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

7 0
3 years ago
URGENT!!!!!! Find the value of q in the following system so that the solution to the system is——
valkas [14]
<h3>Answer:  Q = 8</h3>

====================================================

Explanation:

The left hand side of the first equation is x-3y

The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y

If we multiply both sides of the first equation by 2, we get

x-3y = 4

2(x-3y) = 2*4

2x-6y = 8

Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.

We can say each solution is in the set {(x,y): x-3y = 4}

Which is the same as saying each solution is of the form (3y+4,y)

4 0
4 years ago
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