Answer the questions below based on a bag of Jolly Ranchers having the following number of each flavor:

Mathematics

1 answer:

viva [34]3 years ago

8 0

Part A) About 19/100
Part B) About 4/25
Part C) About 7/20
Part D) About 13/20

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I am so lost, please help

skelet666 [1.2K]

Answer:

$u=\frac{9}{t}-\frac{1}{2} a t$

Step-by-step explanation:

Step 1: Given equation: $9=\frac{1}{2} a t^{2}+u t$

To get u, by subtraction equality property subtract both sides of the equation by $\frac{1}{2} a t^{2}$ .

$\Rightarrow 9-\frac{1}{2} a t^{2}=\frac{1}{2} a t^{2}+u t-\frac{1}{2} a t^{2}$

$\Rightarrow 9-\frac{1}{2} a t^{2}=u t$

Step 2: By division equality property, divide both sides of the equation by t.

$\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}$

$\Rightarrow \frac{9}{t}-\frac{1}{2} a t=u$

Therefore, $u=\frac{9}{t}-\frac{1}{2} a t$ .

So, in Emily’s physics class, she got $u=\frac{9}{t}-\frac{1}{2} a t$ .

7 0

3 years ago

Find the smallest value of k such that the LCM of k and 6 is 60

Advocard [28]

Answer: The smallest valuest value for k is 10, such that LCM of k and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60 is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for k should be 10, such that LCM of k and 6 is 60.

Hence, the smallest value of k is 10.

5 0

3 years ago

Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$