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Mnenie [13.5K]
3 years ago
13

SOMEONE PLEASE HELP ME WITH THIS PROBLEM!!!

Mathematics
1 answer:
sasho [114]3 years ago
5 0

Answer:the last one

Step-by-step explanation:

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"in 2012, total u.s. bottled water consumption increased to 9.67 billion gallons, up from 9.1 billion gallons in 2011. in fact,
Maru [420]

Using proportions, it is found that the estimate of the the per capita consumption from 2011 was of 29.25 gallons.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The amount in 2012 was a increase of 5.3% from 2011, that is, 105.3% = 1.053 of x, and the consumption per capita was of 30.8 gallons, hence:

1.053x = 30.8

x = 30.8/1.053

x = 29.25 gallons.

More can be learned about proportions at brainly.com/question/24372153

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2 years ago
Write a algebraic expression for each verbal expression ​
sashaice [31]

Answer: I don't see the verbal expression

Step-by-step explanation:

4 0
3 years ago
Tomas wants to buy a new baseball bat. The one he likes costs $130, but it is on sale for $104. What is the percent of the disco
Minchanka [31]
130-104=26
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3 0
4 years ago
Read 2 more answers
In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe
enot [183]

Answer:

a)

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that \pi = 0.16

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = z\sqrt{\frac{0.16*0.84}{n}}

0.03\sqrt{n} = z\sqrt{0.16*0.84}

\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}

(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

Question b:

99% confidence level,

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2

n = 990.2

Rounding up

A sample size of 991 is needed.

8 0
3 years ago
Slope = 1/6; (-12,-2)
avanturin [10]
-2,1/6,12 is the slope
8 0
3 years ago
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