Answer:
Number of term = 48
Step-by-step explanation:
GIven:
Arithmetic progression
2,5,8..
Total sum of Arithmetic progression is 392
Find:
Number of term
Computation:
First term a = 2
Difference d = 5 - 2 = 3
Sn = [n/2][2a + (n-1)d]
392 = [n/2][2(2) + (n-1)3]
392 = [n/2][4 + 3n - 3]
784 = [n][1 + 3n]
784 = n + 3n²
3n² + n - 784
n = 48 , n = -49
Number of term = 48
16 x8 will be the new lenth!
Answer: x=2.5y-7
Step-by-step explanation:
Subtract 10 from both sides, resulting in 2x=5y-14
Divide both sides by 2 to isolate the x, resulting in x=(5/2)y-7
(5.)
13x + 5 = 83
-5 -5
13x =78
/13 /13
x = 6
(9.)
0.7 , 0.9 , 1.6 , 2.3 , 2.5
median = 1.6
Step 1 : Setting up the problem
Write the coefficients of the dividend in the same order. For missing terms, enter the co-efficient as zero. Set the divisor equal to zero and use that number in the division box.
The problem now looks as follows:
-1 | 12 5 3 0 -5
Step 2 : Bring down the first co-efficient and write it in the bottom row.
-1 | 12 5 3 0 -5
______________________ 12
Step 3 : Multiply the first coefficient with the divisor and enter the value below
the next co-efficient. Add the two and write the value in the bottom row.
-1 | 12 5 3 0 -5
_____-12_______________ 12 -7
Step 4 : Repeat Step 3 for rest of the coefficients as well:
-1 | 12 5 3 0 -5
____________7 ___________ 12 -7 10
-1 | 12 5 3 0 -5 ______________ -10______ 12 -7 10 -10
-1 | 12 5 3 0 -5 ____________________ 10_ 12 -7 10 -10 5
The last row now represents the quotient coefficients and the remainder. Co-efficients of Quotient are written one power less than their original power and the remainder is written as a fraction.
Answer :12x^3-7x^2+10x-10+5/(x+1) where the last term denotes the remainder and the rest is the quotient.
