Answer:A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution. Solving" systems of linear inequalities means "graphing each individual inequality, and then finding the overlaps of the various solutions". So I graph each inequality, and then find the overlapping portions of the solution regions.Step 1: Line up the equations so that the variables are lined up vertically. Step 2: Choose the easiest variable to eliminate and multiply both equations by different numbers so that the coefficients of that variable are the same. Step 3: Subtract the two equations. Step 4: Solve the one variable system.
Step-by-step explanation:
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Answer:
m∠ABD = 132 °
Step-by-step explanation:
m∠ABE = m∠DBE
and
m∠ABD = m∠ABE + m∠DBE
Because m∠ABE = 66°, therefore m∠DBE = 66°, so that
m∠ABD = 66° + 66° = 132°
Answer:
The answer to your question is: y ≥ - x + 6 and y ≥ x - 4
Step-by-step explanation:
Look of a pairs of points for each graph
Line 1 Line 2
A(0, 6) B (5, 1) C (7,3) D(5, 1)
m = (1- 6) / (5- 0) m = (1 - 3) / (5 - 7)
m = -5/5 = -1 m = -2 / -2 = 1
Find the line equation for each slope (y - y1) = m (x - x1)
(y - 1) = -1 (x - 5) (y - 1) = 1 (x - 5)
y - 1 = -x + 5 y -1 = x - 5
y = -x + 5 + 1 y = x - 5 + 1
y = -x + 6 y = x - 4
Inequality
y ≥ - x + 6 y ≥ x - 4
9514 1404 393
Answer:
y +1 = -3(x -3)
Step-by-step explanation:
The given point is (3, -1), and the given slope is -3. The form suggests you want the point-slope form of the equation for the line:
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Using the given values, the equation is ...
y -(-1) = -3(x -3)
y +1 = -3(x -3)
You add 7+5 together to get 12, then you multiply 12 by 6 and get 72, then you add the 3 to 72 and get 75. 6(7+5)+3. Hope this helps with the problem!!