Answer:
9=-1=?
Step-by-step explanation:
What is the question. Do you want us to evaluate it?
Answer:
2^3 or 8
Step-by-step explanation:
![4^3\div 2^3= \\\\(2^2)^3\div 2^3= \\\\2^{2\cdot 3}\div 2^3= \\\\2^6\div 2^3=\\\\2^{6-3}=\\\\2^3=\\\\8](https://tex.z-dn.net/?f=4%5E3%5Cdiv%202%5E3%3D%20%5C%5C%5C%5C%282%5E2%29%5E3%5Cdiv%202%5E3%3D%20%5C%5C%5C%5C2%5E%7B2%5Ccdot%203%7D%5Cdiv%202%5E3%3D%20%5C%5C%5C%5C2%5E6%5Cdiv%202%5E3%3D%5C%5C%5C%5C2%5E%7B6-3%7D%3D%5C%5C%5C%5C2%5E3%3D%5C%5C%5C%5C8)
Hope this helps!
Hello! To find any number in the arithmetic sequence we can use a formula!
It is given by
![a_n =a_1+(n-1)d](https://tex.z-dn.net/?f=a_n%20%3Da_1%2B%28n-1%29d)
The geometric sequence formula goes by
![S_n = \frac{a_1(1-r^n)}{1-r}](https://tex.z-dn.net/?f=S_n%20%3D%20%20%5Cfrac%7Ba_1%281-r%5En%29%7D%7B1-r%7D%20)
So for this we notice that there's a start of 5 and is being added 3 to get 8.
and then each time it is added by 2 more to get the next time
5
5+ 3 = 8
8 + 5 = 13
13 + 7 = 20
20 + 9 = 29
29 + 11 = 41
41 + 13 = 54
54 + 15 = 69
69 + 17 = 83
Your formula is
![a_n = (n-1)^2 + 4 ](https://tex.z-dn.net/?f=a_n%20%3D%20%28n-1%29%5E2%20%2B%204%0A%0A)
Where n starts at 2 not 1
Trying b and tell me is not correct
Please tell me
The answer for this question is 26