The perimeter of a triangle is equal to the sum of all side lengths in that triangle. We're given the perimeter as 50 inches, and the side lengths as n, 3n + 3, and 2n + 11.

This means that we can algebraically solve the equation $n + 3n + 3 + 2n + 11 = 50$

Step 1: Combine like terms.

$(n+3n+2n) + (3+11) = 50$
$6n + 14 = 50$

Step 2: Subtract 14 from both sides.

$6n + 14 - 14 = 50 - 14$
$6n = 36$

Step 3: Divide both sides by 6.

$6n/6 = 36/6$
$n = 6$

Step 4: Plug in the value of n as 6 in each side.

$(6) + (3(6) + 3) + (2(6)+11) = 50$
$(6) + (18+3) + (12+11) = 50$
$(6) + (21) + (23) = 50$

Therefore, the side lengths are 6, 21, and 23 inches.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0

2 years ago

14. Is x + 2 a factor of the polynomial f(x)=2x-3x²-4x+1?

defon

Thanks for the free 10x+ points .

8 0

3 years ago

Racer and J. Michael are both training for the 1600 meter run. Last

aleksley [76]

Answer:

a lot

Step-by-step explanation:

7 0

3 years ago

What is 4/7 of 70 apples

AlladinOne [14]

Answer:

40 apples

Step-by-step explanation:

4/7 of 70

1. rewrite in mathematical terms

4/7 * 70

2. solve

4/7 * 70

= 40

8 0

3 years ago