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telo118 [61]
4 years ago
10

Which expression is equivalent to the expression below? (x/x+4)/x

Mathematics
2 answers:
exis [7]4 years ago
4 0

Answer:

B) \frac{\frac{x}{x+4}}{x} =  \frac{x}{(x+4)}(\frac{1}{x})

Step-by-step explanation:

Given : \frac{\frac{x}{x+4}}{x}.

To find : Which expression is equivalent to the expression below.

Solution : We have given that \frac{\frac{x}{x+4}}{x}.

By exponent rule  (\frac{\frac{a}{b})}{c}.

⇒  \frac{a}{b} \cdot \frac{1}{c} =   \frac{a}{bc}.

Here a = x , b= x +4 , c =x.

Plugging the values

⇒  \frac{x}{x +4} \xdot \frac{1}{c} =  \frac{x}{x+4·x}.

⇒   \frac{x}{(x+4)} \cdot (\frac{1}{x}).

Therefore,B) \frac{\frac{x}{x+4}}{x} =  \frac{x}{(x+4)}(\frac{1}{x})

mixas84 [53]4 years ago
3 0

Answer:

Option b is correct.

the expression which is equivalent to the expression \frac{\frac{x}{x+4}}{x} is,  \frac{x}{(x+4)}(\frac{1}{x})

Explanation:

Given: The expression is: \frac{\frac{x}{x+4}}{x}

We remember that dividing fraction a by fraction b is the same as multiplying fraction a by the reciprocal of fraction b  or vice versa. Also any number can be expressed as itself over 1.

Using expression:  (\frac{\frac{a}{b})}{c}

⇒ \frac{a}{b} \cdot \frac{1}{c}

Now, we can easily get; \frac{a \cdot 1}{b \cdot c} = \frac{a}{bc}

Let a = x , b = x+4 and c =x

then;

\frac{(\frac{a}{b})}{c} = \frac{a}{bc} = \frac{x}{x \cdot (x+4)}

or we can write it as \frac{x}{(x+4)} \cdot (\frac{1}{x})

Therefore, the expression which is equivalent to the expression \frac{\frac{x}{x+4}}{x} is,  \frac{x}{(x+4)}(\frac{1}{x})


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Which set of measurements could represent the three sides of a triangle?
yawa3891 [41]

Answer:

The side lengths of a right triangle is 11cm, 60cm and 61cm, that could be selected from the given measurements.

Step-by-step explanation:

The measurements are,

                  7cm, 11cm, 54cm, 60cm, 61cm, 65cm

Step:1

                 To check the right angle triangle, Pythagorean theorem can be used.

                For a Pythagorean theorem,

                                     ..........................(1)

               The side values are lower than the hypotenuse,

                                                        ...................................(2)

               Where,

                         a,b - side values

                            c - Hypotenuse

               For right angle triangle,  c > a, b

               Alternative : 1

               Take, a = 7cm, b = 11cm

               From eqn (2),

                                                   =  = 13.04

              The above value is not equal to the any one of the values of ( 54cm. 60cm, 61cm, 65cm ), So its not an sides of right triangle.

               Alternative : 2

               Take, a = 7cm, b = 54cm

               From eqn (2),

                                                   =  = 54.45

              The above value is not equal to the any one of the values of (60cm, 61cm, 65cm ), So its not an sides of right triangle.

               Alternative : 3

               Take, a = 7cm, b = 60cm

               From eqn (2),

                                                   =  = 60.406

              The above value is not equal to the any one of the values of (61cm, 65cm ), So its not an sides of right triangle.

               Alternative : 4

               Take, a = 7cm, b = 61cm

               From eqn (2),

                                                   =  = 61.40

              The above value is not equal to the values of (65cm ), So its not an sides of right triangle.

                 Alternative : 5

               Take, a = 11cm, b = 54cm

               From eqn (2),

                                                   =  = 55.1089

              The above value is not equal to the any one of the values of (60cm, 61cm, 65cm ), So its not an sides of right triangle.      

                Alternative : 6

               Take, a = 11cm, b = 60cm

               From eqn (2),

                                                  =  = 61

              The above value is equal to the values of (61cm ), So its an sides of right triangle. The three sides are 11, 60 and 61.

Step:2

            Check for solution,

                                     

                                           

Result:

            The side lengths of a right triangle is 11cm, 60cm and 61cm, that could be selected from the given measurements.                

Step-by-step explanation: The side lengths of a right triangle is 11cm, 60cm and 61cm.

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The minimum of the function is the y-value of the vertex, 103/8.
=======================================...

Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.

The correct way of doing what dizzle TRIED to do:

For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)

y=18x^2+9x+14

a = 18
b = 9

- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4

Take that value for x, evaluate function at that value to get y.
=======================================...
Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:

x-intercept(s) can be found by setting function equal to zero and solving:

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0 = 18(x + 1/4)^2 + 103/8

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(x + 1/4)^2 = - 103/144

x + 1/4 = +/- i*sqrt(103)/12

x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12

These are the roots of the equation f(x) = 0

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