8
Suppose f(x) = ----------
sqrt(x)
8
What if we let x = 16 (just an example)? We'd get f(16) = ------------- = 2.
sqrt(16)
What if we let x = g(x) = 2x+4?
We'd get the following:
8
f(g(x)) = -------------- = y
sqrt(2x+4)
So...the correct answer is the fourth one.
Answer:
d.
Step-by-step explanation:
Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.
Right line is defined when x is greater or equal to one x ≥ 1.
Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.
Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.
Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)
You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.
Answer:
a) £320
b) £720
c) 2 days
Step-by-step explanation:
The question is all about inputting values and finding a result or rearranging and finding a result.
a) d = 6. C = 50(6)+20 = 320
b) d = 2x7 (7 days a week) C = 50(2x7) + 20 = 720
c) C = 120 ... 120 = 50d+20
100 =50d d = 100/50 = 2
M can be any positive real number.
Explanation:
From f(x) = √(mx) ; if x is posive m has to be positive; if x is negative m has to be negative; if x is cero m can have any value, and the range will always be 0 or positve
From g(x) = m √x; x can only be 0 or positive and the range will have the sign of m.
Given we concluded that the range of f(x) can only be 0 or positive, then me can only be 0 or positive.
Its .097. Just move the decimal
