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erma4kov [3.2K]
3 years ago
14

(11w^4 × 3z^9)(2w^7z^2)​

Mathematics
1 answer:
mart [117]3 years ago
4 0

Simplified:

11w^4(3)z^9(2w^7z^2)

=66w^11z^11

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A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be r
antoniya [11.8K]
The function is h(t) = -16t^2 + 80t + 224, and according to the description of the function in the problem statement, we have the following:

at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:

h(0) = -16(0)^2 + 80(0) + 224=0+0+224=224 (ft), which is the initial height, as expected.


At t=1 (sec), the height would be  h(1) = -16(1)^2 + 80(1) + 224=-16+80+224=288. 

etc.


The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.

This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.


Answer: B) 7 sec



6 0
3 years ago
Read 2 more answers
How do you find y in the rectangle??
expeople1 [14]
34 divided by 14 is 2.42......
Then multiply it by 6 to get your Y.
that is what I think though, I may be wrong
8 0
3 years ago
Solve the equation 4.1g+6=2.1g+12.
SSSSS [86.1K]

Answer:

g=3

Step-by-step explanation:

6 0
3 years ago
Please help!! Will mark first answerer brainiest​!! Thank you so much!!
geniusboy [140]
C. Is the answer to this question
8 0
3 years ago
Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

7 0
3 years ago
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