Let be:Speed of the wind: WSpeed of the plane in still air: P
Against the wind the plane flew:Distance: d=175 milesTime: ta=1 hour 10 minutesta=1 hour (10 minutes)*(1 hour/60 minutes)ta=1 hour + 1/6 hourta=(6+1)/6 hourta=7/6 hourSpeed against the wind: Sa=d/taSa=(175 miles) / (7/6 hour)Sa=175*(6/7) miles/hourSa=1,050/7 miles per hourSa=150 mph
(1) P-W=Sa(1) P-W=150
The return trip only took 50 minutesDistance: d=175 milesTime: tr=50 minutestr=(50 minutes)*(1 hour/60 minutes)tr=5/6 hour
Speed retur trip: Sr=d/trSr=(175 miles) / (5/6 hour)Sr=175*(6/5) miles/hourSr=1,050/5 miles per hourSr=210 mph
(2) P+W=Sr(2) P+W=210
We have a system of 2 equations and 2 unknows:(1) P-W=150(2) P+W=210
Adding the equations:P-W+P+W=150+2102P=360Solving for P:2P/2=360/2P=180
Replacing P by 180 in equation (2):(2) P+W=210180+W=210
Solving for W:180+W-180=210-180W=30
Answers:The speed of the plane in still air was 180 mphThe speed of the wind was 30 mph
Answer:
N= -44/9 Hope this helped, <3
Step-by-step explanation:
Let's solve your equation step-by-step.
n−2=10n+42
Step 1: Subtract 10n from both sides.
n−2−10n=10n+42−10n
−9n−2=42
Step 2: Add 2 to both sides.
−9n−2+2=42+2
−9n=44
Step 3: Divide both sides by -9.
Answer:
<h2>$36.00</h2>
Step-by-step explanation:
$12.00 - the total cost of 4 of equally priced gloves
$12.00 : 4 = $3.00 - the cost of 1 glove
The cost per glove is increased by $1.00. Therefore new cost of 1 glove is
$3.00 + $1.00 = $4.00
The total cost of 9 of gloves at the new price:
9 × $4.00 = $36.00
Rectangle. I hope this helps.
≈5.61