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Ahat [919]
2 years ago
13

Please help! Sketch the graph of each line.

Mathematics
1 answer:
madam [21]2 years ago
4 0

Answer:

1) (-3,0) (0,-3)

2) (-2,0)

3) (5,0) (0,-1)

4) (12,0) (0,3)

5) (-16,0) (0,4)

6) (-0.8333,0) (0,5)

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If x=(10-3i) and y=(3-10i), then xy=? and x/y=?
Solnce55 [7]

Answer:

xy=-109i

\frac{x}{y}=\frac{60}{109}+\frac{91}{109}i

Step-by-step explanation:

xy=(10-3i)(3-10i)

To compute x times y must use foil on the right hand side.

First:  10(3)=30

Outer: 10(-10i)=-100i

Inner: -3i(3)=-9i

Last: -3i(-10i)=30i^2=-30

------------------------------------Add like terms:

-109i

----------------

\frac{x}{y}

\frac{10-3i}{3-10i}

Multiply top and bottom by bottom's conjugate:

\frac{(10-3i)(3+10i)}{(3-10i)(3+10i)}

Foil the top and just do first and last of Foil for the bottom since the bottom contains multiplying conjugates:

\frac{30+100i-9i-30i^2}{9-100i^2}

Replace i^2 with -1:

\frac{30+91i+30}{9+100}

\frac{60+91i}{109}

\frac{60}{109}+\frac{91}{109}i

7 0
3 years ago
A store decreases the price of a sofa by 16% this month only, to $5200. What was the price before the
zheka24 [161]

9514 1404 393

Answer:

  $6190.48

Step-by-step explanation:

The price is now 1 -16% = 84% of the original price (p).

 $5200 = 0.84p

  p = $5200/0.84 = $6190.48

The price before the discount was $6190.48.

3 0
3 years ago
in 2009 a total of R36 000 was invested in two accounts. One account earned 7% annual interest and the other earned 9% .The tota
Akimi4 [234]

a = amount invested at 7%

b = amount invested at 9%

we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000.  We can also say that

\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of a}}{\left( \cfrac{7}{100} \right)a}\implies 0.07a~\hfill \stackrel{\textit{9\% of b}}{\left( \cfrac{7}{100} \right)b}\implies 0.09b

since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.

\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}

5 0
2 years ago
1
myrzilka [38]

Answer:

sorry I can't answer

Step-by-step explanation:

pls thanks me

4 0
3 years ago
The radius of the large sphere is times longer than the radius of the small sphere.
jeka94

Answer:

1/3

Step-by-step explanation:

You can try it I keep getting 3 so maybe that’s the answer

8 0
3 years ago
Read 2 more answers
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