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Brums [2.3K]
3 years ago
12

"10 \frac{1}{2} \div 1 \frac{1}{4} " alt="10 \frac{1}{2} \div 1 \frac{1}{4} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0
10 1/2 divided by 1 1/4 is 8 4/10
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A car weighs 4,000 pounds wich comparison is true
Stella [2.4K]

Answer:

D

Step-by-step explanation:

2000=1 ton so 4000=2tons

4 0
2 years ago
Read 2 more answers
Question 26 pleaseee
LuckyWell [14K]

Answer:

The inequality is 55+10x\leq 105

The greatest length of time Jeremy can rent the jet ski is 5 and Jeremy can rent maximum of 135 minutes.

Step-by-step explanation:

Given: Cost of first hour rent of jet ski is $55

          Cost of each additional 15 minutes of jet ski is $10

          Jeremy can spend no more than $105

Assuming the number of additional 15-minutes increment be "x"

Jeremy´s total spending would be first hour rental fees and additional charges for each 15-minutes of jet ski.

Lets put up an expression for total spending of Jeremy.

\$55+ \$ 10\times x

We also know that Jeremy can not spend more than $105

∴ Putting up the total spending of Jeremy in an inequality.

\$ 55+\$10x\leq \$ 105

Now solving the inequality to find the greatest number of time Jeremy can rent the jet ski,

⇒ \$ 55+\$10x\leq \$105

Subtracting both side by 55

⇒ \$ 10x\leq \$50

Dividing both side by 10

⇒x\leq \frac{50}{10}

∴ x\leq 5

Therefore, Jeremy can rent for 60\ minutes + 5\times 15\\= 60\ minutes + 75= 135\ minutes

Jeremy can rent maximum of 135 minutes.

5 0
3 years ago
1. What is the range? Write your answer like #<br> Helppppppp
Korolek [52]
I don’t know sorry but like how’s yoonbum doing? Also like wanna be friends?
4 0
2 years ago
If John owes 300 dollars and pays 50 a week what are the dependent and independent variables ​
podryga [215]
300 dollars would be the independent variable and 50 dollars a week is dependent
7 0
3 years ago
Fine The slope of the line on the graph
Brrunno [24]

Take any 2 points through which the line on graph passes,

(0,-1) =(x₁,y₁)

& (2,-4)=(x₂,y₂)

slope=(y₂-y₁)/(x₂-x₁)

=[-4-(-1)]/(2-0)

=-3/2

3 0
3 years ago
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