Answer:
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
Corrected question;
In a group of 65 students 10 have brown eyes and 30 have blue eyes. Find the Probability that a student pick from this group at random either has blue or brown eyes
Step-by-step explanation:
Given;
Total number of students = 65
Number of students with either blue or brown eyes;
= 10+30 = 40
The probability that a student pick from this group at random either has blue or brown eyes is
P = 40/65 = 0.6154
P = 61.54%
For this case, the first thing you should do is define a variable.
We have then:
x: number of passengers remaining who can board the plane.
We have as data:
1) They can board up to 149 passengers
2) There are 96 passengers currently aboard.
Writing inequality we have:
Answer:
An inequality that can be used to determine how many more people can board is:
Answer:
b(h) = 4^h
Step-by-step explanation:
The ratio of counts from one hour to the next is 4/1 = 16/4 = 64/16 ... = 4. The count at h=0 is 1, so that is the multiplier of the exponential term.
b(x) = 1×4^h