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xenn [34]
3 years ago
6

Scientific hypotheses differ from scientific theories in that they are

Chemistry
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

A tentative explanations that need further evaluation

Explanation:

In scientific experiment, hypothesis and theories are used. Both are important but significantly different from one another. Scientific hypothesis is a tentative explanation to a problem that needs further evaluation by testing via experimentation. This means that a hypothesis must be testable and subject to proper investigation.

On the other hand, theories are tested explanation. That is, theories are not subject to testing because they are well backed up by data.

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The elements in group 17 of the periodic table are all called halogens. All halogens have the same
goldfiish [28.3K]

The group 17 elements of the periodic table have 7 valence electrons and are highly reactive, with low melting and boiling points. The halogens - including fluorine, chlorine and bromine - have a common tendency to form salts, but they are all of a toxic nature.


https://www.google.com/search?q=what+do+all+halogens+have+in+common&rlz=1C5CHFA_enUS710US710&oq=what+do+all+halogens&aqs=chrome.1.69i57j0l5.6043j0j7&sourceid=chrome&ie=UTF-8


6 0
3 years ago
Read 2 more answers
Unit 2 Test
Dafna11 [192]

Answer:

the answer to this question is producer

3 0
3 years ago
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
Q401YzNjg1/details
Sholpan [36]

Answer:

siof4 su8f adfi5 9id7 mdsyfn8 dsjfd8ie3 4yb4uj 4bnu4b 4uj4k 38h1487y76 bis4can d2f9id  fvs98nd

Explanation:us8s f7  ds8a das8 jf7sd 87sd 45s67f8

8 0
3 years ago
How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten alcl3 with an electrical curre
Brilliant_brown [7]
The correct answer is e. 3.57×10³
Al³+(aq) + 3e→AL(s)
4.00g of AL=4g/26.98 g/mol= 0.1483 mol
t=znF/1 where t is time in seceonds.
Z= valency number of ions of the substance or electrons which are transferred per ion
F= Faraday's constant
I = electric current in'A'CA  C/s
t=(3×0.1483 mol ×96485 C/mol) /12(C15)
t=3577 second = 3.5 ×10³s
8 0
3 years ago
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