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Elden [556K]
3 years ago
14

What are the extensive and intensive properties described in this experiment? Which properties would change and which would stay

the same if you ran the experiment sing 7.5-ounce cans instead of 12- ounce cans?
Chemistry
2 answers:
RUDIKE [14]3 years ago
6 0
No because the amount of the water stays the same
kupik [55]3 years ago
3 0

Answer:

No, because the amount of the matter stays the same.

Explanation:

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If 10.7 grams of NH4Cl is dissolved in enough water to make 800 mL of solution,what will be it's molarity
olga nikolaevna [1]
<h3><u>Answer;</u></h3>

Molarity = 0.25 M

<h3><u>Explanation;</u></h3>

Molarity is given by moles/Liter.

First we find moles:

Number of moles = Mass /molar mass

= (10.7g NH4Cl)/(53.5g/mol NH4Cl)

= 0.200 moles NH4Cl  

Then  we convert to liters:

= (800mL)*(1L/1000mL) = 0.800L  

Therefore; molarity = 0.2moles/0.8L

                                = 0.25M

6 0
3 years ago
Explain how a motorcar engine produces nitrogen oxides
olya-2409 [2.1K]

Answer: combustion causes a chemical reaction between nitrogen and oxygen in the engine.

Explanation:

Nitrogen oxides are produced in combustion processes, partly from nitrogen compounds in the fuel, but mostly by direct combination of atmospheric oxygen and nitrogen in flames. Nitrogen oxides are produced naturally by lightning, and also, to a small extent, by microbial processes in soils.

4 0
3 years ago
Read 2 more answers
Which is an acceptable Lewis structure for a diatomic nitrogen molecule?
madam [21]
Https://quizlet.com/18404690/chemistry-final-flash-cards/ 

here  is a Quizlet I have for that

7 0
4 years ago
A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?
Ainat [17]

Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

4 0
3 years ago
What is the ph of a solution of 0.700 m kh2po4, potassium dihydrogen phosphate?
GalinKa [24]
Molal or molar? There is a difference
4 0
3 years ago
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