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3 years ago

What happens to the energy that is lost when water freezes?

2 answers:

5 0

When water freezes it gives up some of the water's energy. This energy that is given up is the latent heat of freezing. When the water was freezing latent heat of freezing energy was being released. ... When a latent heat process occurs the temperature remains constant.

SVEN [57.7K]3 years ago

4 0

As we know through the principle of conservation of energy, energy can neither be created nor destroyed. Therefore, the energy removed from the water in order to make it freeze is absorbed by the surroundings. This is why the surroundings in which freezing is taking place are below freezing. This is more easily illustrated in the example of condensation. If you were to hold a plate over a pot of boiling water, some of the water would give its energy to the plate and condense on its surface.

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Please help 12 points and ill mark you brainiest .

Elodia [21]

Answer:

Explanation:

wet air is known as water vapor

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3 years ago

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1. Which of the following rules determines the charge on a monatomic Ion formed from a nonmetal?

d1i1m1o1n [39]

1. Which of the following rules determines the charge on a monatomic Ion formed from a nonmetal?C. 8 - group number

2. Which of the following statements is true?
A. Metals lose electrons to become cations.

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4 years ago

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Four ice cubes at exactly 0 ∘c with a total mass of 52.5 g are combined with 160 g of water at 90 ∘c in an insulated container.

horrorfan [7]

Heat gained by ice cubes would be equal to the - heat lost by warm water

The moles of ice is: 50.5 g / 18.0 g/mol = 2.81 mol

Heat required to melt all of the ice is equal to: 2.81 mol X 6.02 kJ/mol = 16.9 kJ = 16890 J

Now, know whether the warm water will still be above 0C when it loses this much heat:
-1690 J = 160 g (4.184 J/gC) (Delta T) Delta T = -25C

In order to solve for the final temperature, going back to include warming of the melted ice to a final temperature:

q(ice/water) = - q(warm water)

moles (Delta Hf) + m c (T2-T1) = - m c (T2-T1)

50.5 g / 18.0 g/mol = 2.81 mol

2.81 mol X 6.02 kJ/mol + 50.5g (4.184 J/gC) (T2-0) = -160g (4.184 J/gC) ( T2-80)

16916 + 211.3T2 = -669.4 T2 + 53555

36639 = 880.7 T2

T2 = 41.6 C

6 0

3 years ago

Read 2 more answers

What is the oxidation number for each atom in NH4CI?

Alika [10]

N = +3, H = +1 ,Cl = -1

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4 years ago

How many moles of oxygen are needed to make 12 moles of magnesium oxide ?

Artemon [7]

Answer:

6 moles of oxygen are needed to make 12 moles of magnesium oxide.

Explanation:

First of all you should know that the balanced chemical equation is:

2 Mg + O₂ → 2 MgO

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

So:

$x=\frac{c*b}{a}$

In this case the rule of three applies as follows: if 2 moles of magnesium oxide are produced from 1 mole of oxygen, 12 moles of magnesium oxide from how many moles of oxygen is produced?

$moles of oxygen=\frac{12 moles of magnesium oxide* 1 mole of oxygen}{2 moles of magnesium oxide}$

moles of oxygen= 6

6 moles of oxygen are needed to make 12 moles of magnesium oxide.

4 0

4 years ago