1/2y^2=1/2x^2+8. The curve's slope at (x,y) is x/y, so dy/dx=x/y. To solve this differential equation, rearrange it to: y*dy=x*dx, and by integrating both sides, we get 1/2y^2=1/2x^2+C (some constant). Plug in (0,4) into this equation, 8=0+C, so C=8. The curve's equation is 1/2y^2=1/2x^2+8.
Tangent theta = opp/adj = 48/36 = 4/3
You are correct. here it is step by step.
[7-(2-5(2)+7)] +2
[7-(2-10+7)]+2
[7-(-1)]+2
8+2
10
Convert to:
42 4 168
---- x ---- = ------
1 7 7
