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Arada [10]
3 years ago
14

URGENT 23-28 with work

Mathematics
1 answer:
dybincka [34]3 years ago
7 0
-5                  This is the answer with the work
 23
-28
-----
   -5
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What is the range of the function f(x) = 3.2x for the domain {-4, -2, 0, 2, 4}?
arsen [322]
The range are all the possible solutions for y. Since the domain is given, these are all the possible x values. To find the range, we can simply substitute each of these x values to the given function <span>f(x) = 3.2x.
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<span>Given the domain, we use this to find the range values,
Domain: {-4, -2, 0, 2, 4}
</span>Range: {-12.8, -6.4, 0, 6.4, 12.8}
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3 years ago
How do you answer this?
antiseptic1488 [7]
They both equal the same thing. 
So you would write/type the answer that they equal the same thing. 

8 0
3 years ago
What is 72<br> x 19<br><br><br><br><br>the answer is what ​
PtichkaEL [24]

Answer:

1368

Step-by-step explanation:

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What are the dimensions for this triangle?
REY [17]

Answer:

2 and 2

Step-by-step explanation:

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4 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
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