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ArbitrLikvidat [17]
3 years ago
10

A 13-foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 7 feet f

rom the base of the building. how high up the wall does the ladder reach?
Mathematics
1 answer:
NARA [144]3 years ago
6 0

Answer:

64

Step-by-step explanation

8 times 8 is 64 just write that down

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Plz help my with this!
Vera_Pavlovna [14]

Answer:

approx.  23

Step-by-step explanation:

4+9+10=23

6 0
3 years ago
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
4 years ago
Multiply. assume that no denominator equals zero x^2-16
lawyer [7]
There's nothing to multiply. However, you can factor it to get (x + 4)(x - 4). 
4 0
3 years ago
Please help
Naya [18.7K]

Answer:

what what's that's I can't understand anything

7 0
3 years ago
Read 2 more answers
A film distribution manager calculates that 4% of the films released are flops. If the manager is correct, what is the probabili
Anit [1.1K]

Answer:

9.34%

Step-by-step explanation:

p = 4%, or 0.04

n = Sample size = 667

u = Expected value = n * p = 667 * 0.04 = 26.68

SD = Standard deviation = \sqrt{np(1-p)}  =\sqrt{667*0.04*(1-0.04)} = 5.06

Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?

This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35

Since,

Z = (X - u) / SD

We have;

Z = (33.35 - 26.68) / 5.06

Z = 1.32

From the Z-table, the p-value of 1.32 is 0.9066

1 - 0.9066 = 0.0934, or 9.34%

Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.

6 0
3 years ago
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