Answer:
There needs to be 300 liters of Drink A and 270 liters of Drink B
Step-by-step explanation:
Let a = the amount of Drink A and b = the amount of Drink B
Multiplying a number by 0.2 is the same as calculating 20% of it and same goes with 15% and 0.15. This makes our equation for the amount of fruit juice:
0.2a + 0.15b = 100.5
We know what the difference between a and b will be 30 liters so:
a - b = 30
Now we have our system of equations
To cancel out a, we can multiply the first equation by -5 so we will now have:
-a - 0.75b = -502.5
a - b = 30
Adding these two equations together, we get:
-1.75b = -472.5
Both sides are negative, so we can take the negative signs away.
1.75b = 472.5
Now divide both sides by 1.75
b = 270
Plugging 270 into b, we have:
a - b = 30
a - 270 = 30
Add 270 to both sides
a = 300
There needs to be 300 liters of Drink A and 270 liters of Drink B
A) 5/12 cup more
you have to convert the fractions so they have the same denominator. 0.75 is 9/12 and 1/3 is 4/12. Subtract and you get 5/12
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we have
The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive
The angle A lie on the II Quadrant
step 1
Find the measure of angle A
using a calculator
step 2
Find the sin(A)
we know that
substitute the value of cos(A)
step 3
Find tan(A)
we know that
substitute the values
Simplify
For a better understanding of the explanation provided here, please find the diagrams in the two files that have been attached.
As can be clearly seen from the diagram, PR and QS are the diameters of the circle and they intersect each other at the centre, O of the circle.
The angle these diameters make at the point of intersection O is 90 degrees.
If Margot joins the points P,Q,R and S which are on the circumference of the circle, then we will get a square with sides PQ, QR, RS and SP as shown in the second diagram.
Thus, the correct option is Option A.
C. It is not always possible to calculate theoretical probability in complex situations, but experimental probability can be calculated any time experiments can be run.
