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mash [69]
3 years ago
6

A researcher is interested in whether people are less able to identify emotions correctly when they are extremely tired. It is k

nown​ that, using a particular method of​ measurement, the accuracy ratings of people in the general population are normally distributed with a mean of 8181 and a variance of 2020. In the present​ study, however, the researcher arranges to test 5151 people who had no sleep the previous night. The mean accuracy for these 5151 individuals was 7979. Using the 0.05​ level, what should the researcher​ conclude
Mathematics
1 answer:
stepan [7]3 years ago
3 0
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By analyzing the given information, we have the following hypothesis:-

H_0:\mu\geq81\\\\H_a:\mu

Since the alternative hypotheses is left tailed so the test is a right-tailed test.

Also, the  accuracy ratings of people in the general population are normally distributed.

Given : Sample size :  n=51 , since n>30 so we use z-test.

Sample mean : \overline{x}=79

Standard deviation : \sigma=\sqrt{20}\approx4.47

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{79-81}{\dfrac{4.47}{\sqrt{51}}}\\\\\Rightarrow\ z\approx-3.195

Critical value (one-tailed) corresponds to the given significance level :-

z_{\alpha}=z_{0.05}=1.645

Since the observed value of z (-3.195) is less than the critical value (1.645) , so we do not reject the null hypothesis.

Hence, we conclude that we do not have enough evidence to accept that people are less able to identify emotions correctly when they are extremely tired .

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