Answer:
I think question is:
(x+4x+2)(2x^2+3x-4)
:(5x+2)(2x^2+3x-4)
5x(2x^2+3x-4)+2(2x^2+3x-4)
10x^3+15x^2-20x+4x^2+6x-8
10x^3+19x^2-14x-8
Answer:
B) [1, 4, 7]
Step-by-step explanation:
Substitute 0 in
f(0) = 3(0) + 1
Multiple
f(0) = 0 + 1
f(0) = 1
Substitute 1 in
f(1) = 3(1) + 1
f(1) = 3 + 1
f(1) = 4
Substitute 2 in
f(2) = 3(2) + 1
2 = 6 + 1
f(2) = 7
Factor out -1
-1(x^2+x-6)
Factor the inner trinomial
-1(x+3)(x-2)
Final answer: B