The correct answer is Cl₂ <CCl₄ < PCl₃ < CaCl₂ < CsCl (most polar)
Cl₂ is nonpolar or least polar as there is no differentiation in electronegativity of the two atoms of chlorine producing amongst them. CCl₄ exhibits four C-Cl bonds. The C-atom is electropositive and Cl is electronegative. Therefore, there are four dipoles in CCl₄. Though, these dipoles cancel each other because of the tetrahedral geometry of the molecule. Therefore, CCl₄ is less polar in comparison to others, however, more polar in comparison to Cl₂.
PCl₃ exhibits three dipoles because of electronegative chlorine atoms, and electropositive phosphorus atom. Though, the configuration of the molecule is trigonal pyramidal, producing it more polar in comparison to CCl₄. The CaCl₂ is ionic compound, therefore, polar in comparison to the covalent bond compounds.
CsCl is ionic compound, however, more polar in comparison to CaCl₂, as there is the higher difference in electronegativity of Cs and Cl compared with that between the Ca and Cl.
Answer: Force disadvantage and distance advantage
Explanation: When mechanical advantage is less than one the force of the strength decreases because input force is greater than output force.
The distance increases ie the object is moving over a long distance.
Example when fishing with a long fishing rod the force applied to move the fish from the water is greater than the weight of the fish itself. The advantage of using the long fishing pole is that the distance over which the fish travels is greatly increased.
Hope this helps. It took me about half an hour before I could get this answer from my various searches. The idea might not be clear but this was what I was able to understand.
Answer:
0.0991 M
Explanation:
Step 1: Write the neutralization reaction between oxalic acid and sodium hydroxide.
H₂C₂O₄ + 2 NaOH = Na₂C₂O₄ + 2 H₂O
Step 2: Calculate the moles of oxalic acid
The molar mass of H₂C₂O₄ is 90.03 g/mol. The moles corresponding to 153 mg (0.153 g) are:
Step 3: Calculate the moles of sodium hydroxide
The molar ratio of H₂C₂O₄ to NaOH is 1:2.
Step 4: Calculate the molarity of sodium hydroxide
<span>The formula actual yield /
theoretical yield is used to calculate the percent yield of a reaction.
This value is a measure of how much product is produced relative to the what is
supposed to be produced. It seems that the given in the problem is incomplete so we cannot really give a specific value. </span>
