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ZanzabumX [31]
3 years ago
12

If 19.7 g of AlI3 is actually produced, what is the percentage yield? 2 Al + 3 I2 → 2 AlI3

Chemistry
1 answer:
tatuchka [14]3 years ago
8 0
<span>The formula actual yield / theoretical yield is used to calculate the percent yield of a reaction. This value is a measure of how much product is produced relative to the what is supposed to be produced. It seems that the given in the problem is incomplete so we cannot really give a specific value. </span>
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A stock bottle of an acid reads: 56% by mass and 1.25 specific gravity. If the molar mass of the acid is 70g, find the mole per
TiliK225 [7]

Answer:

  • <u>10 mol / dm³</u>

Explanation:

Cubic decimeter is the same unit as liter; so, mole per cubic decimeter is mole per liter, and that is the unit of concentration of molarity. Thus, what is asked is the molarity of the solution. This is how you find it.

1. <u>Take a basis</u>: 1 dm³ = 1 liter = 1,000 ml

2. <u>Calculate the mass of 1 lite</u>r (1,000 ml) of solution:

  • density = mass / volume ⇒ mass = density × volume

Here, the density is given through the specific gravity

Scpecific gravity = density of acid / density of water

Take density of water as 1.00 g/ml.

  • density of solution = 1.25 g/ml

  • mass solution = 1.25 g/ml × 1,000 ml = 1,250 g

3. <u>Calculate the mass of solute</u> (pure acid)

  • % m/m = (mass of solute / mass of solution) × 100

  • 56 = mass of solute / 1,250 g × 100

  • mass of solute = 56 × 1,250g / 100 = 700 g

4. <u>Calculate the number of moles of solute</u>:

  • moles = mass in grams / molar mass = 700 g / 70 g/mol = 10 mol

5. <u>Calculate molarity (mol / dm³)</u>

  • M = number of moles of solute / liter of solution = 10 mol / 1 liter = 10 mol/liter.
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Calculate the molarity of H3PO4 when you added 57.3 g into 3,820 mL of water
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22.989769 u

Explanation:

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