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Paul [167]
2 years ago
8

HELP WHOEVER ANSWERS WILL BE MARKED BRAINLIEST

Chemistry
1 answer:
Vika [28.1K]2 years ago
7 0
1) T
2) F- the heart pumps blood
3) T
4) F- atria and ventricles
5) T
6) T
7) T
8) T
9) F- your heart rate goes down but doesn't stop
10) T

1) D
2) B
3) A
4) E
5)C
You might be interested in
Which substances were ionic?
horsena [70]
<h3>Sodium chloride  and Sodium bicarbonate are ionic substances</h3><h3>Further explanation </h3>

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by sharing electrons with covalent bonds or hand over electrons with ionic bonds

Generally, ionic bonds occur in metals and nonmetallic elements.

While covalent bonds occur because of the use of shared electrons. In general, this bond occurs between nonmetallic elements, which has the same electron attraction

Characteristics of ionic compounds include: solid / crystalline form, soluble in water, conduct electricity

Let see the answer choices

  • Oil

It is a covalent compound because part of the hydrocarbon,  a liquid that forms a bond between elements C, H and O, and does not dissolve in water (floats on water)

  • Cornstarch

Obtained from corn which contains glucose which is a carbohydrate. It does not dissolve in water. Contains a bond between C, H and O. Includes covalent compounds

  • Sodium chloride
  • Sodium bicarbonate

Both are ionic compounds, soluble in water, in solid form

NaCl ⇒ Na⁺ + Cl⁻

NaHCO₃⇒ Na⁺ + HCO₃⁻

<h3>Learn more </h3>

ionic bonding

brainly.com/question/1603987

Type of atoms typically form covalent bonds

brainly.com/question/13648552

the ionic compound LiI

brainly.com/question/2732123#

Keywords : ionic, covalent, Oil ,Cornstarch ,Sodium chloride,Sodium bicarbonate

#LearnWithBrainly

6 0
3 years ago
Read 2 more answers
What makes a question testable? Can someone help me on this pls it has to be either a 4-5 sentence! this is a science question.
Alexxandr [17]

Answer:

testable questions are answer through observation or an experiment that provides evidence that the questions connects to the scientific concepts rather the opinion feelings

therefore the question can be tested through observation or experiment

7 0
3 years ago
PLEASE HURRY THIS IS TIMED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
AURORKA [14]

Answer:

if i remember correctly i beleive its A  1.8 x 10^24

but im not for sure  also i think you forgot the 24

Explanation:

5 0
3 years ago
Saturated hydrocarbon molecules may be bonded in which type of structure?
poizon [28]
<span>all of the above can be saturated molecules </span>
3 0
3 years ago
Read 2 more answers
There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

Assuming complete decomposition of both samples,

  • m(\text{Hg}) = m(\text{residure})
  • m(\text{O}) = m(\text{loss})

First compound:

  • m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g

n = m/M; 0.6498 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.048 \; g  / 16 \; g \cdot mol^{-1}= 0.003 \; mol
  • n(\text{Hg atoms}) = 0.6018 \; g  / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol

Oxygen and mercury atoms seemingly exist in the first compound at a 1:1 ratio; thus the empirical formula for this compound would be \text{Hg} \text{O} where the subscript "1" is omitted.

Similarly, for the second compound

  • m(\text{O}) = m(\text{loss}) = 0.016 \; g
  • m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012  \; g

n = m/M; 0.4172 \; g of the first compound would contain

  • n(\text{O atoms}) = 0.016 \; g  / 16 \; g \cdot mol^{-1}= 0.001 \; mol
  • n(\text{Hg atoms}) = 0.4012 \; g  / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol

n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

8 0
3 years ago
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