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ahrayia [7]
4 years ago
7

What do you understand by the term positron?

Chemistry
1 answer:
egoroff_w [7]4 years ago
5 0

Answer:

A positron is a subatomic particle with the same mass as an electron and a numerically equal but positive charge.

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Ocean water contains 3.5 % NaCl by mass. What mass of ocean water in grams contains 46.8 g of NaCl?
Luda [366]

Answer:

1.3 kg

Explanation:

Mass of ocean water = mass of NaCl × (mass of ocean water/mass NaCl).

The % NaCl tells us there are 3.5 g NaCl/100 g ocean water or 100 g ocean water/3.5 g NaCl.

Mass of ocean water = 46.8 × (100/3.5)

Mass of ocean water = 46.8 × 28.6

Mass of ocean water = 1300 g = 1.3 kg

<em>Note</em>: The answer can have only <em>two significant figures</em> because that is all you gave for the percentage of NaCl.

5 0
4 years ago
The conversion factor that is present in almost all stoichiometry calculations is called the ________ __________ .
Kruka [31]
Mole=mass/molecular mass (Mr)
mole=volume/ 22.4
Molecular amount: Mole=amount atoms/ Avogadro's number 
Concentration: mole=volume x M
5 0
3 years ago
WILL GIVE BRAINLIEST
natta225 [31]

Answer:

It is greater than -600kJ/mol and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.

Explanation:

In an endothermic reaction, the reaction requires a determined amount of energy to occurs.

The reaction of the problem has H = -600kJ/mol. The reaction is endothermic and the energy that the reaction needs is absorbed by the reactants. That means, the energy of products:

Is greater than -600kJ/mol and the amount of energy required to break bonds is greater than the amount of energy released in forming bonds.

7 0
3 years ago
Plzzzzzzzzzzzzzzzz help
Anna [14]

Answer:

Your correct.

Explanation:

5 0
3 years ago
Read 2 more answers
One mole of an ideal monatomic gas is expanded from an initial state at 3 bar and 450 K to a final state at 2 bar and 250K.
Lady bird [3.3K]

Answer:

a) W = 820J, Q = 3314J =

b) For Path A ; ∆U= -2494J, ∆S = -8.85J/K

For Path B ; ∆U = -2494J, ∆S = -8.85J/K

Explanation:

The step by step and mathematical application is as shown in the attached files.

6 0
3 years ago
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