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elena-s [515]
3 years ago
5

What is the symbol for the mole​

Chemistry
2 answers:
blagie [28]3 years ago
7 0

Answer:

6.022x10^23

Explanation:

Mrac [35]3 years ago
3 0
It is just M.
**********
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KMnO4<br><br> Assign oxidation numbers to each element in this compound.
zysi [14]

K=+1

Mn= +7

O= -2

That’s it!!!

8 0
3 years ago
How many grams of Ca(OH)2are required to make 1.5 L of a 0.81 M solution?
FrozenT [24]

Answer:

Mass = 90.28 g

Explanation:

Given data:

Mass of Ca(OH)₂ = ?

Volume of solution= 1.5 L

Molarity of solution = 0.81 M

Solution:

First of all we will calculate number of moles.

Molarity = number of moles / volume in L

by putting values,

0.81 M = Number of moles / 1.5 L

Number of moles = 0.81 M × 1.5 L

Number of moles = 1.22 mol

Mass of Ca(OH)₂ in gram:

Mass = number of moles × molar mass

Mass = 1.22 mol × 74.09 g/mol

Mass = 90.28 g

5 0
3 years ago
A can of soda is 335ml what is 2 cans of soda in ml
Snezhnost [94]
I can =335ml
2cans=?

2cans×335ml÷1
= 670ml
5 0
3 years ago
How many grams of Kr are in a 9.59 L cylinder at 46.0 'C and 4.62 atm?<br> mass:
Sladkaya [172]

Answer:

Mass = 141.6 g

Explanation:

Given data:

Mass of Kr in gram =  ?

Volume in L = 9.59 L

Temperature = 46.0°C

Pressure = 4.62 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

46.0+273 = 319 K

4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K  ×319 K

44.3 atm.L = n×26.19 atm.L/ mol

n = 44.3 atm.L / 26.19 atm.L/ mol

n = 1.69 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1.69 mol × 83.79 g/mol

Mass = 141.6 g

8 0
3 years ago
What is the correct IUPAC name for S2F8?
notka56 [123]

Answer:

Question: What Is The Correct IUPAC Name For S2F8? X ( ( (I) (IV) Di- Mono- Penta- Tetra- Tri- Hepta- Octa- Hexa- Fluorine Selenide Flourate Sulfide Sodium Sulfate Sulfur Fluoride Hydrate Acid.

8 0
3 years ago
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