The moon is not visible during which phase

PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres

chubhunter [2.5K]

Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

$PV=nRT$

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

$P=\frac{nRT}{V}$

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

$32+273=305$

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

$\frac{28.0}{28.01} \\=.99$ moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

$R=62.36\frac{torr}{mol*K}$

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

$P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36$

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

6 0

3 years ago

The partial pressure of hellium gas in a gaseous mixture of hellium and hydrogen is<br>

RUDIKE [14]

Answer:

The partial pressure of helium gas in a gaseous mixture of helium and hydrogen is the pressure that the helium would exert in the absence of the hydrogen. equal to the total pressure divided by helium's molar mass. O equal to the total pressure divided by the number of helium atoms present.

Hope this Helps (✿◡‿◡)

8 0

3 years ago

Under what circumstances might be important to know the activity tendencies of elements?

ad-work [718]

Answer: It is very important to know the activity tendencies of the elements. The activity tendencies tells us about whether the element is reactive or not.

In the redox-reaction where there is a need to know the oxidizing agent and reducing agent, we can know it easily from the activity tendencies. The elements lying above the reactivity series are better reducing agents.

In the substitution reactions, the activity tendencies helps us to know which element will replace the other. The element lying above in the series will replace the element lying below it.

$MX+NY \rightarrow MY+NX$

where, N is an element that lies above in the reactivity series

M is an element that lies below in the reactivity series

3 0

3 years ago

The following substituents are listed in random order. Using the Cahn–Ingold–Prelog convention, rank the groups below from highe

Ivahew [28]

Answer:

-SH, -CH2SH, - CH2CH2SH, -H,

7 0

3 years ago

2. If the reaction of 5.75 moles of sodium with excess hydrofluoric acid is able to produce 2.49 mol H2, what is the percent yie

GuDViN [60]

Answer:

86.5%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Na + 2HF –> 2NaF + H2

Next, we shall determine the theoretical yield of the hydrogen gas, H2. This is illustrated:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole of H2.

Therefore, 5.75 moles of Na will react to produce = (5.75 x 1)/2 = 2.88 moles of H2.

Therefore, the theoretical yield of Hydrogen gas, H2 is 2.88 moles.

Finally, we shall determine the percentage yield of Hydrogen gas, H2. This can be obtained as follow:

Actual yield of H2 = 2.49 moes

Theoretical yield of H2 = 2.88 moles

Percentage yield of H2 =.?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 2.49/2.88 x 100

Percentage yield = 86.5%

Therefore, the percentage yield of Hydrogen gas, H2 is 86.5%.

6 0

3 years ago