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3 years ago

The moon is not visible during which phase

Chemistry

2 answers:

vaieri [72.5K]3 years ago

5 0

I believe the answer is B. new moon

Tanzania [10]3 years ago

4 0

The answer would be B. New Moon.

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Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c

steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

$2CuO+C\rightarrow 2Cu+CO_2$

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide = $\frac{907185 g}{79.55 g/mol}=11,403.95 moles$

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

$\frac{1}{2}\times 11403.95 mol=5,701.98 mol$ of carbon

Mass of 5,701.98 moles of carbon:

$5,701.98 mol\times 12 g/mol=68,423.75 g$

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

$95\%=\frac{68,423.75 g}{x}\times 100$

$x=720,250.09 g=0.794 Ton$

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0

3 years ago

Question 4 of 10

frez [133]

Answer: D. Slow down the chain reaction by absorbing free neutrons

Explanation: just got it right on the quiz A P E X

3 0

2 years ago

To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu

VikaD [51]

The answer is <span>D.when the aim is to show electron distributions in shells. This is because there are some instances when elements don't possess a regular or normal electron configuration. There are those who have special electron configurations wherein a lower subshell isn't completely filled before occupying a higher subshell. It is best to visualize such cases using the orbital notation.</span>

8 0

2 years ago

Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuri

Fed [463]

Answer:

a) 88.48%

b) 0.05625 mol

Explanation:

2CH₃CH₂OH(l) → CH₃CH₂OCH₂CH₃(l) + H₂O(g) Reaction 1

CH₃CH₂OH(l) → CH₂═CH₂(g) + H₂O(g) Reaction 2

a) CH₃CH₂OH = 46.0684 g/mol

CH₃CH₂OCH₂CH₃ = 74.12 g/mol

1 mol CH₃CH₂OH ______ 46.0684 g

x ______ 50.0 g

x = 1.085 mol CH₃CH₂OH

1 mol CH₃CH₂OCH₂CH₃ ______ 74.12 g g

y ______ 35.9 g

y = 0.48 mol CH₃CH₂OCH₂CH₃

100% yield _____ 0.5425 mol CH₃CH₂OCH₂CH₃

w _____ 0.48 mol CH₃CH₂OCH₂CH₃

w = 88.48%

b) Only 0.96 mol of ethanol reacted to form diethyl ether. This means that 0.125 mol of ethanol did not react. 45% of 0.125 mol reacted to form ethylene. Therefore, 0.05625 mol of ethanol reacted by the side reaction (reaction 2). Since 1 mol of ethanol leads to 1 mol of ethylene, 0.05625 mol of ethanol produces 0.05625 mol of ethylene.

4 0

3 years ago

calculate the volume that will be occupied by 350 ml of oxygen measured at 720 mm hg, when the pressure changed to 630 mm hg

likoan [24]

Answer:

406.45mL

Explanation:

The following data were obtained from the question:

V1 = 350mL

P1 = 720mmHg

P2 = 630mmHg

V2 =?

The new volume can be obtain as follows:

P1V1 = P2V2

720 x 350 = 620 x v2

Divide both side by 620

V2 = (720 x 350) /620

V2 = 406.45mL

The new volume of the gas is 406.45mL

8 0

3 years ago