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lisabon 2012 [21]
3 years ago
5

The moon is not visible during which phase

Chemistry
2 answers:
vaieri [72.5K]3 years ago
5 0

I believe the answer is B. new moon

Tanzania [10]3 years ago
4 0
The answer would be B. New Moon.
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Calculate the mass, in grams, of a single xenon atom (mxe = 131.29 amu ).
Mariana [72]

Answer is 2.18017\times10^{-22}gms.

Explanation: To calculate the mass of 1 Xe-atom , we will require atomic mass of Xe which is 131.29amu.

This atomic mass is the mass of 1 mole of 1 Xe-atom. One mole of Xe-atom is 6.022\times10^{23} atoms of Xe. We will use this relation to convert Mass of Xe-atom into grams.

\frac{\text{mass of 1 atom}}{atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}atoms}

\text{mass of 1 atom}=\frac{\text{mass of 1 mole of atom}}{6.022\times10^{23}}

\text{mass of 1 Xe-atom}=\frac{131.29}{6.022\times10^{23}}

\text{mass of 1-Xe atom}=21.8017\times10^{-23}gms

                                               =2.18017\times10^{-22}gms


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3 years ago
How do valence electrons affect the properties of atoms?
Ymorist [56]
It determines the manner in which it develops bonds.... so, it affect ionization energy, electronegativity, metallic characteristic, formation of oxides etc.
6 0
3 years ago
How much is 35° C in F?
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It's 95 F
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4 years ago
How many grams of Kr are in a 8.55 L cylinder at 12.3 ∘C and 8.33 atm?
NISA [10]

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I think its 0.301

Explanation:

8 0
3 years ago
Describe the buffer capacity of the acetic acid buffer solution in relation to the addition of both concentrated and dilute acid
AysviL [449]

Answer:

The answer is in the explanation

Explanation:

Acetic acid, CH₃COOH, is a weak acid that will produce a buffer when its conjugate base, CH₃COO⁻, acetate ion, is added to the solution.

<em>That is because a buffer is the mixture of a weak acid and its conjugate base or vice versa.</em>

When an acid (HX) is added to the solution, the acetate ion will react producing acetic acid, thus:

CH₃COO⁻ + HX → CH₃COOH + X⁻

For this reason, the pH doesn't change abruptly because H⁺ ions are not produced.

Now, if a  base (BOH) is added to the buffer, CH₃COOH will react producing acetate ion and water, thus:

CH₃COOH + BOH → CH₃COO⁻ + H₂O + B⁺.

In the same way, there are not produced free OH⁻ and the pH doesn't change significantly.

5 0
3 years ago
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