0.09(70x+1) is the answer to this question
Answer:
1. x = √(73)/2 - 9/2 or x = -9/2 - √(73)/2
2. x = (512 2^(1/3) + (18 i √(16303) + 16222)^(2/3))/(6 (9 i √(16303) + 8111)^(1/3)) + 16/3 or x = 16/3 + (256 (-1)^(2/3))/(3 (1/2 (9 i √(16303) + 8111))^(1/3)) - 1/3 ((-1)/2)^(1/3) (9 i √(16303) + 8111)^(1/3) or x = ((-2)^(2/3) (9 i √(16303) + 8111)^(2/3) - 512 (-2)^(1/3))/(6 (9 i √(16303) + 8111)^(1/3)) + 16/3 or x = 1/3 (10 - 3 √(11))^(-1/3) ((-1)^(1/3) (10 - 3 √(11))^(2/3) - (-1)^(2/3)) - 1/3 or x = 1/3 ((-10 - 3 √(11))^(1/3) - (-1)^(1/3) (3 √(11) - 10)^(1/3)) - 1/3 or x = 1/3 (10 - 3 √(11))^(-1/3) (-(10 - 3 √(11))^(2/3) - 1) - 1/3
3. x = 2/5 or x = (i √(3))/2 - 1/2 or x = -(i √(3))/2 - 1/2
4. x = 1/4 + (4 √(54714) + 441)^(1/3)/(4 3^(2/3)) - 61/(4 (12 √(54714) + 1323)^(1/3)) or x = (-(-3)^(1/3) (4 √(54714) + 441)^(2/3) - 61 (-3)^(2/3))/(12 (4 √(54714) + 441)^(1/3)) + 1/4 or x = (61 (-3/(441 + 4 √(54714)))^(1/3) + (-1)^(2/3) (441 + 4 √(54714))^(1/3))/(4 3^(2/3)) + 1/4
Step-by-step explanation:
Too long! I try to add to the comments!
Answer:
36 mph
Step-by-step explanation:
First, we have to find the unit rate of the money.
Since it's 15 dollars for each mile over the speed limit, divide 15 by 165.
The answer is 11, which means he was going 11 mph over the speed limit.
Add 11 to 25, and you get 36
Make ur life easier by reducing the fraction first. divide both numbers by 100
now u have 7/2
now divide 7 by 2, u would get 3.5
